Which number can be used as a common denominator for the fractions One-fourth and FIve-sixths?

mixer [17]

You are everything, you are loved :)

4 0

3 years ago

Emily’s lawn grows at a constant rate. The height of her lawn, during a 10-day period, is represented by the graph below.

galina1969 [7]

Answer:

I think the answer would be C 16 days.

I cant really see the bottom of the graph

Step-by-step explanation:

5 0

3 years ago

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An open rectangular box with a square bottom must have a surface area of A square inches. Write a formula for the volume of the

skelet666 [1.2K]

The surface area of the box is being referred to as A
The surface area will be the sum of the four rectangular sides' areas and the base area.
Base area = x²
Rectangular side area = xh
A = x² + 4xh
Volume is, as you said,
V = x²h
Lets substitute h from the formula of A to obtain A in our final answer. Substituting x is possible, but more difficult
(A - x²)/4x = h
V = (x²) * (A - x²)/4x
V = (Ax - x³)/4

5 0

3 years ago

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What is the slope of each line

timama [110]

Answer:2 or 2/1

Step-by-step explanation:

Start a 0

Count up until the line perfectly hits in the center of the lines

6 0

3 years ago

(1 point) The effectiveness of a new bug repellent is tested on 18 subjects for a 10 hour period. Based on the number and locati

jolli1 [7]

Answer:

z=1.59

If we compare the p value and the significance level given $\alpha=0.025$ we see that $p_v>\alpha$ so we can conclude that we fail to reject the null hypothesis, so we can conclude that the mean repellency of the new bug repellent is greater than 89% at 0.025 of signficance.

Step-by-step explanation:

1) Data given and notation

$\bar X=0.92$ represent the mean effectiveness of a new bug repellent for the sample

$\sigma=0.08$ represent the population standard deviation for the sample

$n=18$ sample size

$\mu_o =0.89$ represent the value that we want to test

$\alpha=0.025$ represent the significance level for the hypothesis test.

t would represent the statistic (variable of interest)

$p_v$ represent the p value for the test (variable of interest)

State the null and alternative hypotheses.

We need to conduct a hypothesis in order to determine if the mean repellency of the new bug repellent is greater than 89% or 0.89, the system of hypothesis would be:

Null hypothesis: $\mu \leq 0.89$

Alternative hypothesis: $\mu > 0.89$

We don't know the population deviation, and the sample size <30, so for this case is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:

$t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}$ (1)

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".

Calculate the statistic

We can replace in formula (1) the info given like this:

$t=\frac{0.92-0.89}{\frac{0.08}{\sqrt{18}}}=1.59$

Calculate the P-value

First we need to calculate the degrees of freedom given by:

$df=n-1=18-1=17$

Since is a one-side upper test the p value would be:

$p_v =P(t_{17}>1.59)=0.065$

In Excel we can use the following formula to find the p value "=1-T.DIST(1.59;17;TRUE)"

Conclusion

If we compare the p value and the significance level given $\alpha=0.025$ we see that $p_v>\alpha$ so we can conclude that we fail to reject the null hypothesis, so we can conclude that the mean repellency of the new bug repellent is greater than 89% at 0.025 of signficance.

6 0

4 years ago