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Deffense [45]
3 years ago
10

For a store contest, 4 out of every 65 people who visit the store will receive a free DVD if 455 people visit how many DVDs were

given away
Mathematics
2 answers:
harina [27]3 years ago
8 0
28 people will get a free DVD because 455/65=7 and 7*4=28
insens350 [35]3 years ago
7 0

Answer:

28 DVDs will be distributed.

Step-by-step explanation:

For a store contest out of 65 people 4 people receive a free DVD.

We have to calculate the number of DVDs distributed when 455 people visit the store.

We will apply the unitary method to find the number of DVDs distributed.

∵ When 65 people visit the store number of DVDs = 4

∴ when 1 person visit the store then number of DVDs distributed = \frac{4}{65}

∴ When 455 people visit the store then DVDs distributed = \frac{4\times 455}{65}

= 28

Therefore, 28 DVDs will be distributed.

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Answer:

C. \frac{1}{18}

Step-by-step explanation:

Given: Six cards numbered from 1 to 6 are placed in an empty bowl. First one card is drawn and then put back into the bowl then a second card is drawn.

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Sample space for sum of cards when two cards are drawn at random is \{(1,1),(1,2),(1,3)......(6,6)\}

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Sample space when sum of cards is 8 is \{(3,5),(5,3),(6,2),(2,6),(4,4)\}

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Sample space when one of the cards is 5 is \{(5,3),(3,5)\}

Total number of possible cases =2

Let A be the event that sum of cards is 8

p(\text{A}) =\frac{\text{total cases when sum of cards is 8}}{\text{all possible cases}}

p(\text{A})=\frac{5}{36}

Let B be the event when one of the two cards is 5

probability than one of two cards is 5 when sum of cards is 8

p(\frac{\text{B}}{\text{A}})=\frac{\text{total case when one of the number is 5}}{\text{total case when sum is 8}}

p(\frac{\text{B}}{\text{A}})=\frac{2}{5}

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p(\text{A and B}=p(\text{A})\times p(\frac{\text{B}}{\text{A}})

p(\text{A and B})=\frac{5}{36}\times\frac{2}{5}

p(\text{A and B})=\frac{1}{18}

if sum of cards is 8 then probability that one of the cards is 8 is \frac{1}{18}, option C is correct.

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