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navik [9.2K]
3 years ago
12

Scores on the SAT college entrance test in a recent year were roughly Normal with mean 1012.5 and standard deviation 184.9. You

choose an SRS of 90 students and average their SAT scores. If you do this many times, the mean of the average scores you get will be close to
Mathematics
1 answer:
kondor19780726 [428]3 years ago
6 0

Answer:

By the Central Limit Theorem, the mean of the average scores you get will be close to 1012.5.

Step-by-step explanation:

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

Mean score of the population:

1012.5

If you do this many times, the mean of the average scores you get will be close to

By the Central Limit Theorem, the mean of the average scores you get will be close to 1012.5.

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The formula F=9/5C+32 converts temperatures from Celsius C to Fahrenheit F. A. Solve the formula for C b. The boiling point of w
liraira [26]

Answer:

(a) \therefore C=\frac59(F-32)

(b)The boiling point of water in Celsius scale is 100°C.

(c)The setting in Celsius scale is 26.7°C.

Step-by-step explanation:

Given that,the formula is

F=\frac95 C+32......(1)

(a)

Given that,

F=\frac95 C+32

\Rightarrow F-32=\frac95 C+32-32     [ subtracting 32  from both sides]

\Rightarrow F-32=\frac95 C

\Rightarrow \frac95 C=F-32

\Rightarrow C=\frac59(F-32) ......(2)         [Multiplying \frac59  ]

\therefore C=\frac59(F-32)

(b)

Given that, the boiling point of water is 212°F.

Putting F=212 in equation (2)

\therefore C=\frac59(212-32)

\Rightarrow C=\frac59\times 180

\Rightarrow C=5\times 20

\Rightarrow C=100

The boiling point of water is 100°C.

(c)

Given that, a house thermostat is set at 80 degree.

Putting F=80 in equation (2)

\therefore C=\frac59(80-32)

\Rightarrow C=\frac59\times 48

\Rightarrow C\approx26.7

The setting in Celsius scale is 26.7°C.

7 0
3 years ago
What is the volume of 1.5 Tonne of sand of density 2600 kg/m3?  <br>​
Mrac [35]

Answer: 0.58 m^3

Step-by-step explanation:

V= 2600 / 1500

= 0.58 m^3

5 0
3 years ago
A suit originally costing $240 is on sale for 25% off the original price. Sales tax is 7.5%. What is the final cost of the suit?
slava [35]

Answer:

$193.50

Step-by-step explanation:

start by multiplying 240 by .25 (25%) to find out how much is 25% of 240. this equals 60.

then, subtract $60 from $240. equals 180.

next, to add the sales tax, multiply 180 by 0.075 (7.5%) this is $13.50.

lastly, add the tax, which is $13.50, to the suit's sale price, which is $180.

180+13.5= $193.50

7 0
3 years ago
Find the value of f(3) for the function f(x) = -4(x+1)-2
lora16 [44]

Answer:

f(3) = - 18

Step-by-step explanation:

To evaluate f(3) , substitute x = 3 into f(x) , that is

f(3) = - 4(3 + 1) - 2 = - 4(4) - 2 = - 16 - 2 = - 18

6 0
3 years ago
Sharika can finish the work in 6 days and Palkey can do the same work in 8 days. They both worked together for for 2 days then P
Rufina [12.5K]

Answer:

Sharika needs 2.5 days to finish the remaining work

Step-by-step explanation:

Sharika can do a work in 6 days palkey can do it in 8 days

Then the amount of work sharika can do in 1 day = 1/6

And the amount of work palkey can do in 1 day = 1/8

The amount of work both of them can do together in 1 day = 1/6 + 1/8

= 7/24

The amount of work both of them can do together in 2 day = (2× 7/24)

= 7/12

Since Palkey left the work,the amount of

work remaining for Sharika to do alone = (1 - 7/12 )

= 5/12

The number of days Sharika take to finish the remainig work. = (5/12 ÷ 1/6 )

= 5/2 days

Therefore, Sharika needs 2.5 days to finish the remaining work.

5 0
3 years ago
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