Answer:
its a
Step-by-step explanation:
Answer:
The coordinates of the other end is 
Step-by-step explanation:
Given


Required
Find the coordinates of the other end
Let Midpoint be represented by (x,y);
(x,y) = (5,2) is calculated as thus

So
and 
Where
and 
So, we're solving for 
Solving for 
Substitute 5 for x and -6 for x₁

Multiply both sides by 2


Add 6 to both sides


Solving for 

Substitute 2 for y and 2 for y₁

Multiply both sides by 2


Subtract 2 from both sides



Hence, the coordinates of the other end is 
Answer: after 3 days
Step-by-step explanation: Step-by-step explanation: The sister has to pay rent which is $60 which means she has negative $30 in three days the sister would have earned $60 and in 3 days the brother would have earned $60
The actual block is 1800 feet long and 1260 feet wide. We know that 1 foot is equivalent to 12 inches.
Luke is now using the Feet scale measurement.
Solving for the area in square inches is shown below:
Area = L * W
Area = (1800 feet *12 inches/1 foot) * (1260 feet *12 inches/1 foot)
Area = 326.592 x10^6 inches²
Answer:
proper fraction
Step-by-step explanation:
Mixed number has a whole number and a fraction a b/c
Improper fraction has a numerator that is greater than the denominator a/b where a is greater than b a>b
Proper fraction has a numerator that is less than the denominator a/b where a is less than b a<b