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Tcecarenko [31]
3 years ago
7

A recent national survey found that high school students watched an average (mean) of 7.1 movies per month with a population sta

ndard deviation of 1.0. The distribution of number of movies watched per month follows the normal distribution. A random sample of 33 college students revealed that the mean number of movies watched last month was 6.2. At the 0.05 significance level, can we conclude that college students watch fewer movies a month than high school students? State the null hypothesis and the alternate hypothesis.
Mathematics
1 answer:
muminat3 years ago
3 0

Answer:

H0: μc ≤ μs    Ha :μc > μs    

Step-by-step explanation:

The null and alternate hypotheses can be stated as

H0: μc ≤ μs    Ha :μc > μs    one tailed test

Where

μc =  Mean of college students watching movies in a month

μs  =  Mean of school students watching movies in a month

For one tailed test of α =0.05   the value of Z= ± 1.645

The critical region will be Z >  ± 1.645

It is of importance to note that by rejecting the null hypothesis and accepting the alternate hypothesis we are automatically rejecting all values of mean that are greater than 7.1

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Answer:

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Step-by-step explanation:

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Find the dimensions of a rectangle with perimeter 68 m whose area is as large as possible. (If both values are the same number,
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Answer:

<h2>Length is 17m and Breadth is also 17m</h2>

Step-by-step explanation:

The perimeter of a rectangle is expressed as 2(L+B) where;

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P = 2(L+B)

68 = 2(L+B)

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Area of the rectangle A = LB... 2

Substituting equation 1 into 2 will give;

A = (34-B)B

A = 34B-B²

To maximize the area of the triangle, dA/dB must be equal to zero i.e

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34-2B = 0

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Dividing both sides of the equation by 2 we will have;

B = 34/2

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Substituting B = 17 into equation 1 to get the length L

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