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Alenkinab [10]
3 years ago
15

Can anyone help pls ? This is my last question pls

Mathematics
2 answers:
JulijaS [17]3 years ago
7 0

Answer:

107

Step-by-step explanation:

(3+10^2)+4

10^2=10x10=100

3+100=103

103+4=107

Bogdan [553]3 years ago
3 0

Answer:

107

Step-by-step explanation:

Pemdas - Parantheses First

3+10 2 (p<em>e</em>mdas)

10*10=100+3=103 Parantheses Done!

103+4=107

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Solve 6 over x minus 3 equals 3 over x for x and determine if the solution is extraneous or not
Natali5045456 [20]

Answer:

<em>x = 1</em>

This is the equation that I interpreted:

6/(x) - 3 = 3/(x)

I have never worked with determining extraneous equations before, so I cannot answer the second part.

8 0
3 years ago
Graph<br>f(x) = 3 |x| + 9
Anastaziya [24]

Answer:

see graph

Step-by-step explanation:

to find points on the graph, enter in x values and find y.

3|-4|+9 =  21  (-4, 21)

3|2|+9 = 15  (2, 15

6 0
3 years ago
PLEASE ANSWER + BRAINLIEST!!!!
zavuch27 [327]

Answer:100 + 3.2t = b


Step-by-step explanation: first off i would organize the data then find the varible(s) after you have all of the data organized with the verible(s) then find what number the varibles belong to. after that is done you would make

the equation which should look like 100 + 3.2t = b


8 0
3 years ago
Plutonium–238 has a yearly decay constant of 7.9 × 10-3. If an original sample has a mass of 15 grams, how long will it take to
eduard
The answer is 28 years

At = A0 * e^(-k * t)
At = 12 g
A0 = 15 g
k = 7.9 × 10^-3 = 0.0079 
t = ?

12 = 15 * e^(-0.0079 * t)
12/15 = e^(-0.0079 * t)
0.8 = e^(-0.0079 * t)

Logarithm both sides (because ln(e) = 1:
ln(0.8) = ln(e^(-0.0079 * t))
ln(0.8) = (-0.0079 * t) * ln(e)
-0.223 = -0.0079 * t
t = -0.223 / -0.0079
t = 28.23
t ≈ 28 years
8 0
3 years ago
How do you find volume of a octagonal prism?
mixer [17]

Answer:

V=2(1+2)a2h

Step-by-step explanation:

8 0
2 years ago
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