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3 years ago

15

Can anyone help pls ? This is my last question pls

2 answers:

JulijaS [17]3 years ago

7 0

Answer:

107

Step-by-step explanation:

(3+10^2)+4

10^2=10x10=100

3+100=103

103+4=107

Bogdan [553]3 years ago

3 0

Answer:

107

Step-by-step explanation:

Pemdas - Parantheses First

3+10 2 (p<em>e</em>mdas)

10*10=100+3=103 Parantheses Done!

103+4=107

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Write the explicit formula for the geometric sequence below. 6,30,150,175

yawa3891 [41]

Answer:

Well it's 5x

Step-by-step explanation:

Idk why the answer's so complicated.

4 0

2 years ago

If x=5 and y=2<br> ...........................

azamat

${ \bold{ - 5}}$

${ \red{ \tt{given \: {\to}}}} \: { \bold{x = 5}} \: \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: { \bold{y = 2}}$

${ \green{ \tt{ \sqrt{10y + x} - xy}}}$

${ \green{ \tt{ \sqrt{10(2) + 5 } - 5(2)}}}$

${ \green{ \tt{ \sqrt{20 + 5} - 10}}}$

${ \green{ \tt{ \sqrt{25} - 10}}}$

${ \green{ \tt{5} - 10}}$

$= { \bold{ - 5}}$

8 0

7 months ago

Read 2 more answers

A cell site is a site where electronic communications equipment is placed in a cellular network for the use of mobile phones. Th

Olegator [25]

Answer:

(a) 74553

(b) 172120

(c) 234802

Step-by-step explanation:

Given

$y = \frac{340110}{1 + 377e^{-0.259t}}$

Solving (a): 1998

Year 1998 means that:

$t =1998 - 1980$

$t =18$

So, we have:

$y = \frac{340110}{1 + 377e^{-0.259*18}}$

$y = \frac{340110}{1 + 377e^{-4.662}}$

$y = \frac{340110}{1 + 3.562}$

$y = \frac{340110}{4.562}$

$y = 74553$ --- approximated

Solving (b): 2003

Year 2003 means that:

$t = 2003 - 1980$

$t =23$

So, we have:

$y = \frac{340110}{1 + 377e^{-0.259*23}}$

$y = \frac{340110}{1 + 377e^{-5.957}}$

$y = \frac{340110}{1 + 0.976}$

$y = \frac{340110}{1.976}$

$y = 172120$ --- approximated

Solving (c): 2006

Year 2006 means that:

$t = 2006 - 1980$

$t =26$

So, we have:

$y = \frac{340110}{1 + 377e^{-0.259*26}}$

$y = \frac{340110}{1 + 377e^{-6.734}}$

$y = \frac{340110}{1 + 0.4485}$

$y = \frac{340110}{1.4485}$

$y = 234802$ --- approximated

3 0

2 years ago

Find the percent increase in the price per cheese stick.

BaLLatris [955]

Take the price of the cheese stick then divide that by the old price. you will get a decimal. New divided by old. You should have some decimal that is 1.something. If its a percent increase of 64 percent you'd have 1.64 as the decimal. good luck.

3 0

3 years ago

What is the expression in radical form?<br><br> (4x3y2)310

sertanlavr [38]

Given:

Consider the given expression is

$(4x^3y^2)^{\frac{3}{10}}$

To find:

The radical form of given expression.

Solution:

We have,

$(4x^3y^2)^{\frac{3}{10}}=(2^2)^{\frac{3}{10}}(x^3)^{\frac{3}{10}}(y^2)^{\frac{3}{10}}$

$(4x^3y^2)^{\frac{3}{10}}=(2)^{\frac{6}{10}}(x)^{\frac{9}{10}}(y)^{\frac{6}{10}}$

$(4x^3y^2)^{\frac{3}{10}}=(2)^{\frac{3}{5}}(x)^{\frac{9}{10}}(y)^{\frac{3}{5}}$

$(4x^3y^2)^{\frac{3}{10}}=\sqrt[5]{2^3}\sqrt[10]{x^9}\sqrt[5]{y^3}$ $[\because x^{\frac{1}{n}}=\sqrt[n]{x}]$

$(4x^3y^2)^{\frac{3}{10}}=\sqrt[5]{8y^3}\sqrt[10]{x^9}$ $[\because x^{\frac{1}{n}}=\sqrt[n]{x}]$

Therefore, the required radical form is $\sqrt[5]{8y^3}\sqrt[10]{x^9}$ .

8 0

3 years ago