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Lunna [17]
3 years ago
12

250 employees in an organization were surveyed about their hair color and height the data collected is presented in the table if

a person selected at random what is the probability that the person is at least 175cm tall
Mathematics
1 answer:
storchak [24]3 years ago
5 0

Answer

0.7

Step-by-step explanation:

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Given the four digits 2, 4, 6, and 7, how many different positive two-digit integers can be formed using these digits if a digit
Mekhanik [1.2K]

Answer: 12

Step-by-step explanation:

Given the question :

Given the four digits 2, 4, 6, and 7, how many different positive two-digit integers can be formed using these digits if a digit may not be repeated in an integer?

The number of different positive two integer number can be obtained by:

P(4, 2) = 4P2

Recall:

nPr = n! / (n - r)!

4P2 = 4! / (4 - 2)!

4P2 = 4! / 2!

4P2 = (4 * 3 * 2 * 1) / ( 2 * 1)

4P2 = 24 / 2

4P2 = 12

Hence, 12 different positive two-digit integers can be formed using these digits if a digit may not be repeated in an integer

7 0
3 years ago
Simplify the following expression as much as possible.
djverab [1.8K]
1 is the answer to this solution
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3 years ago
Hey could someone helpp me pls
Minchanka [31]

Answer: $5.54

Step-by-step explanation: 63 divided by 100 is 0.63, 0.63 x 8.8 is 5.544 and 5.544 rounded to the nearest cent is $5.54

5 0
3 years ago
What is the slope intercept equation of the line below?
igor_vitrenko [27]

Answer:

The answer should be B.

7 0
3 years ago
Last​ year, a person wrote 139 checks. Let the random variable x represent the number of checks he wrote in one​ day, and assume
viktelen [127]

Answer:

Mean = 0.38082 checks per day

Variance = 0.38082

Standard deviation = 0.61711

Step-by-step explanation:

In a Poisson distribution, the variance (V) is equal to the mean value (μ), and the standard deviation (σ) is the square root of the variance.

A year has 365 days,, if 139 checks were written during a year, the mean number of checks written per day is:

E(x)=\mu=\frac{139}{365}\\ \mu=0.38082\ checks/day

Therefore, the variance and standard deviation are, respectively:

V=\mu=0.38082\\\sigma=\sqrt{V}=\sqrt{0.38082}\\ \sigma =0.61711

4 0
4 years ago
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