Answer: 12
Step-by-step explanation:
Given the question :
Given the four digits 2, 4, 6, and 7, how many different positive two-digit integers can be formed using these digits if a digit may not be repeated in an integer?
The number of different positive two integer number can be obtained by:
P(4, 2) = 4P2
Recall:
nPr = n! / (n - r)!
4P2 = 4! / (4 - 2)!
4P2 = 4! / 2!
4P2 = (4 * 3 * 2 * 1) / ( 2 * 1)
4P2 = 24 / 2
4P2 = 12
Hence, 12 different positive two-digit integers can be formed using these digits if a digit may not be repeated in an integer
1 is the answer to this solution
Answer: $5.54
Step-by-step explanation: 63 divided by 100 is 0.63, 0.63 x 8.8 is 5.544 and 5.544 rounded to the nearest cent is $5.54
Answer:
Mean = 0.38082 checks per day
Variance = 0.38082
Standard deviation = 0.61711
Step-by-step explanation:
In a Poisson distribution, the variance (V) is equal to the mean value (μ), and the standard deviation (σ) is the square root of the variance.
A year has 365 days,, if 139 checks were written during a year, the mean number of checks written per day is:

Therefore, the variance and standard deviation are, respectively:
