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3 years ago

Please help! I have been stuck on this all day and its 1:00!!!!!! Please help!

Mathematics

1 answer:

erastova [34]3 years ago

8 0

Answer:

820.05 i guess

Step-by-step explanation:

addeverything together

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The baby giraffe weighed 132 pounds at birth. He gained weight at a steady rate for the first 7 months until his weight reached

Goshia [24]

Answer: 77 pounds each month I think

Step-by-step explanation:

7 0

4 years ago

Read 2 more answers

Please help me Due in an hour

vladimir1956 [14]

131.88 or jus do radius times 2 so 21+ 21 = 42.

42 x pi(3.14) = 131.88

3 0

3 years ago

Write the equation of the quadratic function that passes through the points (-1, 1), (1, 5), and (2,10).

Serjik [45]

Answer:

$\displaystyle f(x)=x^2+2x+2$

Step-by-step explanation:

System Of Linear Equations

In this problem, we'll need to solve a 3x3 system of linear equations because we have three unknowns and three conditions.

We are required to find the equation of the quadratic function that passes through the points (-1, 1), (1, 5), and (2,10)

The general quadratic function can be written as

$\displaystyle f(x)=ax^2+bx+c$

We need to find the values of a,b, and c. Let's use the first condition, i.e. f(-1)=1

$\displaystyle f(-1)=a(-1)^2+b(-1)+c$

$\displaystyle f(-1)=a-b+c$

$\displaystyle a-b+c=1.....[eq\ 1]$

Now we use the second condition f(1)=5

$\displaystyle f(1)=a(1)^2+b(1)+c$

$\displaystyle f(1)=a+b+c$

$\displaystyle a+b+c=5.......[eq\ 2]$

Finally, we use the third condition f(2)=10

$\displaystyle f(2)=a(2)^2+b(2)+c$

$\displaystyle f(2)=4a+2b+c$

$\displaystyle 4a+2b+c=10....[eq\ 3]$

We put together eq 1, eq 2, and eq 3 to form the system

$\displaystyle \left\{\begin{matrix}a-b+c=1\\ a+b+c=5\\ 4a+2b+c=10\end{matrix}\right.$

Adding the first two equations we have

$\displaystyle 2a+2c=6$

$\displaystyle a+c=3$

And also

$\displaystyle b=2$

Using the above equation and the value of b in the third equation, we have

$\displaystyle \left\{\begin{matrix}a+c=3\\ 4a+c=6\end{matrix}\right.$

Subtracting the first equation from the second

$\displaystyle 3a=3$

$\displaystyle a=1$

And therefore

$\displaystyle c=2$

Now we have all the values, the quadratic function is

$\displaystyle \boxed{f(x)=x^2+2x+2}$

6 0

3 years ago

The frist brand is 30% and the second on is 55% in order to obtain 30 gallons of mixture that contains 35% how many gallons of e

snow_tiger [21]

yeet

first brand quantity is x

2nd brand quantity is y

x+y=30

0.3x+0.55y=0.35(30) or 0.3x+0.55y=10.5

solve for x and y

multiply first equation by -0.3

-0.3x-0.3y=-9

add to 2nd equation

0.3x-0.3y=-9

0.3x+0.55y=10.5 +

0x+0.25y=1.5

0.25y=1.5

divide both sides by 0.25

y=6

sub back

x+y=30

x+6=30

x=24

you need 24 gallons of the first brand and 6 gallons of the 2nd brand

4 0

3 years ago

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Circumstance of 12yd

marusya05 [52]

Answer: 40.82yd

Step-by-step explanation:

First of all, it's ''circumference'' and second of all, it's ''13yd''.

$Formula: C=2\pi r$

2r is the same as d = diameter,

$C=\pi d$

$C=(3.14)(13)\\C=40.82yd$

5 0

3 years ago

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