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mash [69]
3 years ago
15

Is the relation below a function? -3 -1 -1 3 у 0 1 2 3

Mathematics
2 answers:
wolverine [178]3 years ago
8 0

Answer:

<h3>I would say no!</h3>

Step-by-step explanation:

<h3>cause we cannot determine the rule of mapping so y is no an image of x</h3>
qaws [65]3 years ago
5 0

Answer:

I believe it would be "y"

Step-by-step explanation:

Function, in mathematics, an expression, rule, or law that defines a relationship between one variable (the independent variable) and another variable (the dependent variable).

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James is framing a rectangular print for art class and needs to know the perimeter. The length of the print is 24 inches and the
ollegr [7]

Answer:

84

Step-by-step explanation:

Given,

Length of the print(l) = 24 inches

Width of the print(b) = 18 inches

Perimeter of the print(P)= ?

We know,

Perimeter of the print(P) = 2(l + b)

= 2(24 + 18)

= 2(42)

=84 inches^2

5 0
3 years ago
1000 x 1000 = ????????????????
bonufazy [111]

Answer:

1,000,000

Step-by-step explanation:

1000 x 1000 = 1,000,000

8 0
3 years ago
Read 2 more answers
Circle the equation with roots 4 and -8
Arisa [49]
Wih roots r1 and r2
the factors are (x-r1)(x-r2)

roots 4 and -8
(x-4)(x-(-8))
(x-4)(x+8)
x^2+4x-32 is the equation


either (x-4)(x+8) or x^2+4x-32
4 0
3 years ago
Expand and simplify:<br>(x + 1)(2x - 3)<br>with the explaining the steps​
Luden [163]
<h3>Answer:  2x^2 - x - 3</h3>

====================================

Work Shown:

(x+1)(2x-3)

y(2x-3)

2xy - 3y

2x( y ) - 3( y )

2x( x+1 ) - 3( x+1 )

2x^2+2x - 3x-3

2x^2 - x - 3

Explanation:

In the second step, I replaced all of (x+1) with y. Afterward, I distributed that y term through. A few steps later, I replaced y with x+1 to help finish up the distributions. You could use the FOIL rule as an alternative approach.

8 0
3 years ago
Read 2 more answers
Which value of x makes this equation true?<br> –5(r = 20) 35
zloy xaker [14]

Answer:

r = -140

Step-by-step explanation:

Isolate the variable by dividing each side by factors that don't contain the variable.  Not sure if this was the answer you were looking for.

8 0
3 years ago
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