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Rudiy27
3 years ago
12

AD=3, BD=5, AE=4. Find CE

Mathematics
1 answer:
EastWind [94]3 years ago
5 0

Answer:

6.6

Step-by-step explanation:

Triangles ADE and ABC are similar.

Therefore,

AD/AB=AE/AC

3/8=4/AC

3AC=32

AC=10.6(3 s.f)

CE=10.6-4=6.6

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Write the 5th term in the expansion of (5x-y/2)^7
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Answer:

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Step-by-step explanation:

Using binomial expansion

Formula: (n k) (a^k)(b ^(n-k))

Where (n k) represents n combination of k (nCk)

From the question k = 5 (i.e. 5th term)

n = 7 (power of expression)

a = 5x

b = -y/2

....................

Solving nCk

n = 7

k = 5

nCk = 7C5

= 7!/(5!2!) ------ Expand Expression

=7 * 6 * 5! /(5! * 2*1)

= 7*6/2

= 21 ------

.........................

Solving (a^k) (b^(n-k))

a = 5x

b = -y/2

k = 5

n = 7

Substituting these values in the expression

(5x)^5 * (-y/2)^(7-5)

= (3125x^5) * (-y/2)²

= 3125x^5 * y²/4

= (3125x^5)(y²)/4

------------------------------------

Multiplying the two expression above

21 * (3125x^5)(y²)/4

= 65625/4(x^5)(y²)

5 0
3 years ago
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5 0
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8 0
4 years ago
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Lisa [10]

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