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Neko [114]
3 years ago
12

(01.05) Use the graph below to answer this question: graph of line going through negative 1, 4 and 2, 0 Find the average rate of

change for the given function from x = −1 to x = 2.

Mathematics
2 answers:
Ainat [17]3 years ago
8 0

Answer:

-4/3

Hope This Helps

give Brainliest if you please :p

dsp733 years ago
4 0

1) Find the graph of a line passing through (-1, 4) and (2, 0).

The slope of two points can be determined by dividing the difference of y-values by the difference of x-values:

\frac{4-0}{-1-2} =\frac{4}{-3}

The slope of this equation is -4/3. Inputting this into the slope-intercept form of an equation, we get:

y=\frac{-4}{3} x+b

To find b, substitute x and y for one of the given coordinate pairs:

0 = (-4/3)(2) + b

0 = -8/3 + b

8/3 = b

Substitute the b value into the equation to finish the line:

y=\frac{-4}{3} x+\frac{8}{3}

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7 0
3 years ago
the initial vertical velocity of a rocket shot straight up is 42 meters per second. How long does it take for the rocket to retu
Snowcat [4.5K]
It takes 4.3 seconds for the rocket to return to earth.

The equation is:
0=-9.8t^2+v_0t+h_0
where -9.8m/sec² is the acceleration due to gravity, v₀ is the initial velocity, and h₀ is the initial height.  We will go from the assumption that the rocket is launched from the ground, so h₀=0, and we are told that the initial velocity, v₀, is 42.  This gives us:

0=-9.8t^2+42t

We will use the quadratic formula to solve this.  The quadratic formula is:
x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}

Plugging in our information we have:
t=\frac{-42\pm \sqrt{42^2-4(-9.8)(0)}}{2(-9.8)}&#10;\\&#10;\\=\frac{-42\pm \sqrt{1764-0}}{-19.6}&#10;\\&#10;\\=\frac{-42\pm \sqrt{1764}}{-19.6}&#10;\\&#10;\\=\frac{-42\pm 42}{-19.6}=\frac{-42-42}{-19.6} \text{ or } \frac{-42+42}{-19.6}&#10;\\&#10;\\=\frac{-84}{-19.6}\text{ or }\frac{0}{-19.6}&#10;\\&#10;\\=4.3\text{ or }0

x=0 is when the rocket is launched; x=4.3 is when the rocket lands.
8 0
3 years ago
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