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The curved surface area of a cylinder is 24cm²
Given the following data;
Base circumference = 4 cm
Height = 6 cm
<h3>How to find the curved surface area of a cylinder?</h3>
Suppose that:
Radius of the considered cylinder = 'r' units
Height of the considered cylinder = 'h' units
Then, the curved surface area of that cylinder is 2πr h
To find the curved surface area (CSA) of the cylinder we have;
CSA of a cylinder = 2πrh
But 2πr = 4 cm
Now Substituting the values into the equation, we have,
CSA of a cylinder = 6 x 4
CSA of a cylinder = 24 cm²
Hence, The curved surface area of a cylinder is 24cm²
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Answer:
5770 feet
Step-by-step explanation:
The height of the wall under the Waters proposal is 20 feet and the height of the wall under the Barrett proposal is 34 feet and its perimeter is 9809 feet. Since there is an increase in the dimensions of the wall, we find this percentage increase.
So, the percentage increase in the height of the wall is thus (New height - Old height)/Old height × 100%
New height = 34 feet and Old height = 20 feet
So, Percentage increase = (New height - Old height)/Old height × 100% = (34 ft - 20 ft)/20 ft × 100 % = 14/20 × 100% = 7/10 × 100% = 70 % increase.
Since all the dimensions increase by the same amount, the perimeter in the Waters proposal increases by 70% to the perimeter in the Barrett proposal.
Let P = perimeter in the Waters proposal and P' = perimeter in the Barrett proposal.
So, the percentage increase in perimeter is
(P' - P)/P × 100 % = 70 %
We now find P
(P' - P)/P = 70%/100%
(P' - P)/P = 0.7
P' - P = 0.7P
P' = 0.7P + P
P' = 1.7P
P = P'/1.7
So, substituting the value for P' = 9809 feet
P = P'/1.7
= 9809 ft/1.7
= 5770 feet
So, the perimeter of the wall under the Waters Proposal is 5770 feet.
110 x 10 - 4 x 7
1,100 - 28
1,072
Answer:
Woolsthorpe Manor House
Step-by-step explanation: