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Leto [7]
3 years ago
11

Thanks this answer really helped I got %100 on my test

Mathematics
2 answers:
Vikki [24]3 years ago
6 0
What are you talking about?
Rzqust [24]3 years ago
3 0
I don’t understand if this is a math problem or a statement.
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Suppose that y is inversely proportional to the 4th power of x, and that y=16 when x=6. What is y when x=3? Round your answer to
Ede4ka [16]
Please I’m I right ??

7 0
2 years ago
Read 2 more answers
State the equation of the line in y = mx + b form.
gtnhenbr [62]
Your slope is wrong! Your slope is going to be 3/2, or C for the first problem. Your y intercept is wrong! Your Y- intercept is actually (0, -1.3) or B for the second problem.
Your equation is going to be
y= 3/2x-1.3
4 0
3 years ago
Prove the function f: R- {1} to R- {1} defined by f(x) = ((x+1)/(x-1))^3 is bijective.
Eduardwww [97]

Answer:

See explaination

Step-by-step explanation:

given f:R-\left \{ 1 \right \}\rightarrow R-\left \{ 1 \right \} defined by f(x)=\left ( \frac{x+1}{x-1} \right )^{3}

let f(x)=f(y)

\left ( \frac{x+1}{x-1} \right )^{3}=\left ( \frac{y+1}{y-1} \right )^{3}

taking cube roots on both sides , we get

\frac{x+1}{x-1} = \frac{y+1}{y-1}

\Rightarrow (x+1)(y-1)=(x-1)(y+1)

\Rightarrow xy-x+y-1=xy+x-y-1

\Rightarrow -x+y=x-y

\Rightarrow x+x=y+y

\Rightarrow 2x=2y

\Rightarrow x=y

Hence f is one - one

let y\in R, such that f(x)=\left ( \frac{x+1}{x-1} \right )^{3}=y

\Rightarrow \frac{x+1}{x-1} =\sqrt[3]{y}

\Rightarrow x+1=\sqrt[3]{y}\left ( x-1 \right )

\Rightarrow x+1=\sqrt[3]{y} x- \sqrt[3]{y}

\Rightarrow \sqrt[3]{y} x-x=1+ \sqrt[3]{y}

\Rightarrow x\left ( \sqrt[3]{y} -1 \right ) =1+ \sqrt[3]{y}

\Rightarrow x=\frac{\sqrt[3]{y}+1}{\sqrt[3]{y}-1}

for every y\in R-\left \{ 1 \right \}\exists x\in R-\left \{ 1 \right \} such that x=\frac{\sqrt[3]{y}+1}{\sqrt[3]{y}-1}

Hence f is onto

since f is both one -one and onto so it is a bijective

8 0
3 years ago
Simplify expression<br>8x-6+x-1​
charle [14.2K]

Answer:

9x -7

Step-by-step explanation:

8x-6+x-1​

Combine like terms

8x +x   -6-1

9x -7

8 0
3 years ago
George wrote an integer. The opposite of George’s integer is -53. Which of these statements about George’s integer must be true?
vlabodo [156]

The George's integer must be true for option D)I and IV.

What is integer?

 A full number (not a fraction) that can be positive, negative, or zero is called an integer . -5, 1, 5, 8, 97, and 3, 043 are some examples of integers. 1.43, 1 3/4, 3.14, and other numbers are examples of non-integer numbers. Integer, which means full or whole in Latin, is the root of the English term integer. A particular category of numbers called integers includes zero, positive numbers, and negative numbers. All whole numbers, both negative and positive, and 0 are considered integers.

Here the opposite of George integer is -53.

We know that opposite value of x is -x.

Then George integer is 53.

George integer must be true for The given options I. the integer is 53 and IV.The integer has absolute value of 53.

Therefore the correct option is  D) I and IV.

To learn more about integer refer the below link

brainly.com/question/13723636

#SPJ9

5 0
1 year ago
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