Answer:
j=7
Step-by-step explanation:
11j-20=6j+15
-6j -6j
5j-20=15 Isolate the variable:
+20 +20
5j=35 Divide to get variable by itself
j=7
Hope this helps :)
There are 4 semicircles, each radius is 8cm, so we get the total areas of these semicircles: 4×0.5×
π
and the square area: 16²
so the total area of figure: 16²+4×0.5×
π=256+128π
The following can be deduced from the expressions
m ∠ D = 4 × m ∠ A
m ∠ B = 3 × m ∠ A-12
Please note that the sum of angles in a triangle is 180 degress. Therefore,
M∠ A + m ∠ B + m ∠ D = 180equation(3)
Substitute for equation 1 and 2 in equation 3 as shown below
m ∠ A + 3 × m ∠ A - 12^0 + 4 x m ∠ A =180^0
m ∠ A + 3 × m ∠ A + 4 x m ∠ A = 180^0+12^0
8m ∠ A = 192^0
m ∠ A= 192^0/8
m ∠ A=24^0
Substitute for m∠A= 24 in equation 1 and 2 as shown below
m ∠ D = 4 × m ∠ A
m ∠ D = 4 × 24^0
m ∠ D = 96^0
m ∠ B = 3 × mA - 12^0
m ∠ B = 3 × 24^0 - 12
m ∠ B = 72^0 - 12^0
,
∠= °
∠= °
∠= °
Answer:
The length side of the original square banner was 9 ft
Step-by-step explanation:
Let
x-----> the length side of the original square banner
we know that
The new area of the banner is equal to
Solve for x
Solve the quadratic equation by graphing
The solution is x=9 ft
see the attached figure
Nick has tennis practice every sixth day = 6
Mark has tennis practice every 4th day = 4
They both had tennis practice on = 31st July
We have to find when will be the next time that they both have practice on the same day?
For this, we will find the LCM of 4 and 6
So, LCM of 4 and 6 is 12.
So, it will be 12 days after 31st July, that they will practice on the same day.
So it is 12th August.
