<h2>
Maximum area is 25 m²</h2>
Explanation:
Let L be the length and W be the width.
Aidan has 20 ft of fence with which to build a rectangular dog run.
Fencing = 2L + 2W = 20 ft
L + W = 10
W = 10 - L
We need to find what is the largest area that can be enclosed.
Area = Length x Width
A = LW
A = L x (10-L) = 10 L - L²
For maximum area differential is zero
So we have
dA = 0
10 - 2 L = 0
L = 5 m
W = 10 - 5 = 5 m
Area = 5 x 5 = 25 m²
Maximum area is 25 m²
Answer:
A) 24
Step-by-step explanation:
4!
4 x 3 x 2 x 1
24
Speed = slope of the line = 20 / 0.5 = 40 km / hr
Second part will be a line with downward slope from the end of the horizontal line Slop = 20 / 1/3 (=60 km/h) So it will pass through the 65 on horizontal axis.
Answer: 5 11/28
Improper Fraction Answer: 151/28
Decimal Answer: 5.3928571
Answer:
A) 555
Step-by-step explanation:
555/3 = 185
Check and make sure; 185 x 3 = 555
Hope this helps!
-Jerc
