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3 years ago

Determine if the two triangles are congruent. If they are, state the condition.

Mathematics

2 answers:

Nataly_w [17]3 years ago

8 0

Answer:

Step-by-step explanation:

They are both Right triangles (a given set of triangles are congruent if the corresponding lengths of their hypotenuse and one leg are equal.)

RideAnS [48]3 years ago

5 0

Answer:

Step-by-step explanation:

Since we have two pairs of congruent sides with the included angle, one pair of which are the hypotenuses, then the triangles are congruent by HL.

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Which relations are functions?<br><br><br><br> Choose all answers that are correct.

-Dominant- [34]

Hello!

In a function, each input has only one output. In A, three has two outputs, 4 and 5, so A is not a function.

In B, you can use something called the vertical line test to see if each x value has one y value as an output. You move an imaginary vertical line across the graph, and if it intersects with two points it is not a function. If we do this on our graph, it will not intersect two points. Therefore, B is a function.

In C, we can see that each input has one output, or there are all different inputs, so C is a function.

For D we can use that vertical line test again. It intersects both the points (-1,1) and (-1,6) so D is not a function

Our final answers are B and C.

I hope this helps!

6 0

3 years ago

Read 2 more answers

Which best describes the composition of transformations that maps ΔLMN to ΔL′M′N′?

Andrews [41]

We can’t answer the question because we need a graph or points.

4 0

3 years ago

Brook makes this conjecture: Because the angles are equal, the proportion of area of each sector relative to the area of the giv

AnnZ [28]

Answer:

The Brooks conjecture is true as the proportion of the area of a sector to the area of a circle is only dependent on the angle.

Step-by-step explanation:

The area of a sector for a radius r and an angle θ is given as

$\Delta Sector=\dfrac{1}{2}r^2\theta$

Whereas the area of a circle for a radius r is given as

$\Delta Circle=\pi r^2$

Now the ratio is given as

$\dfrac{\Delta Sector}{\Delta Circle}=\dfrac{\dfrac{1}{2}r^2\theta}{\pi r^2}$

Here as r is the radius of the circle and it is the same therefore the above ratio is simplified to

$\dfrac{\Delta Sector}{\Delta Circle}=\dfrac{\theta}{2\pi }$

Here as π is constant the only variable here is θ. Thus according to Brooks conjecture when the angles are equal, the proportion of area of each sector relative to the area of the given circle is also equal is true.

6 0

3 years ago

Is 5*9=4666666445554646444646

Step2247 [10]

Answer:

No, it is 45

Step-by-step explanation:

5*9=45

6 0

3 years ago

Evaluate the expression when b= 2 and c=-5. -b+6c

BARSIC [14]

Answer:

-32

Step-by-step explanation:

- 2 + 6 * -5 = -32

6 0

3 years ago

Read 2 more answers