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The second one because since n is not negative then nothing will be in the denominator
H(t) = t^(3/4) - 3t^(1/4)
The critical points can be evaluated by taking the first derivative and equating to 0.
h'(t) = 3 / t^(1/4) - 3 / 4t^(3/4)
3 / (4t^(3/4)) = 3 / t^(1/4)
4t^(3/4) = t^(1/4)
4 = 1/√t
t = 1/16, t = -1/16
Answer:
I don't really see two or three points that are coplanar, so My guess would have to be either point G, E, or F.
A) a number that is divisible by ten is also factors of five
