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elena-s [515]
3 years ago
10

In the diagram below, O is circumscribed about quadrilateral DEFG. What is the value of x?

Mathematics
1 answer:
Fofino [41]3 years ago
7 0

Answer:

A. 70

Step-by-step explanation:

The given quadrilateral DEFG is a cyclic quadrilateral.

\angle F+70\degree=180\degree...opposite angles of a cyclic quadrilateral are supplementary.

\implies \angle F=180\degree-70\degree

\implies \angle F=110\degree

The sum of angles in a quadrilateral is 360 degrees.

x-10+70+110+120=360

x+290=360

x=360-290

x=70\degree

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In triangle RST, m∠R > m∠S + m∠T. Which must be true of triangle RST? Check all that apply.
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Answer:

1. m∠R > 90°

2. m∠S + m∠T < 90°

4. m∠R > m∠T

5. m∠R > m∠S

Step-by-step explanation:

<h3>General strategy</h3>
  1. prove the statement starting from known facts, or
  2. disprove the statement by finding a counterexample

Helpful fact:  Recall that the Triangle Sum Theorem states that m∠R + m∠S + m∠T = 180°.

<u>Option 1.  m∠R > 90°</u>

Start with m∠R > m∠S + m∠T.

Adding m∠R to both sides of the inequality...

m∠R + m∠R > m∠R + m∠S + m∠T

There are two things to note here:

  1. The left side of this inequality is 2*m∠R
  2. The right side of the inequality is exactly equal to the Triangle Sum Theorem expression

2* m∠R > 180°

Dividing both sides of the inequality by 2...

m∠R > 90°

So, the first option must be true.

<u>Option 2.  m∠S + m∠T < 90°</u>

Start with m∠R > m∠S + m∠T.

Adding (m∠S + m∠T) to both sides of the inequality...

m∠R + (m∠S + m∠T) >  m∠S + m∠T + (m∠S + m∠T)

There are two things to note here:

  1. The left side of this inequality is exactly equal to the Triangle Sum Theorem expression
  2. The right side of the inequality is 2*(m∠S+m∠T)

Substituting

180° > 2* (m∠S+m∠T)

Dividing both sides of the inequality by 2...

90° > m∠S+m∠T

So, the second option must be true.

<u>Option 3.  m∠S = m∠T</u>

Not necessarily.  While m∠S could equal m∠T, it doesn't have to.  

Example 1:  m∠S = m∠T = 10°;  By the triangle sum Theorem, m∠R = 160°, and the angles satisfy the original inequality.

Example 2:  m∠S = 15°, and m∠T = 10°;  By the triangle sum Theorem, m∠R = 155°, and the angles still satisfy the original inequality.

So, option 3 does NOT have to be true.

<u>Option 4.  m∠R > m∠T</u>

Start with the fact that ∠S is an angle of a triangle, so m∠S cannot be zero or negative, and thus m∠S > 0.

Add m∠T to both sides.

(m∠S) + m∠T > (0) + m∠T

m∠S + m∠T > m∠T

Recall that m∠R > m∠S + m∠T.

By the transitive property of inequalities, m∠R > m∠T.

So, option 4 must be true.

<u>Option 5.  m∠R > m∠S</u>

Start with the fact that ∠T is an angle of a triangle, so m∠T cannot be zero or negative, and thus m∠T > 0.

Add m∠S to both sides.

m∠S + (m∠T) > m∠S + (0)

m∠S + m∠T > m∠S

Recall that m∠R > m∠S + m∠T.

By the transitive property of inequalities, m∠R > m∠S.

So, option 5 must be true.

<u>Option 6.  m∠S > m∠T</u>

Not necessarily.  While m∠S could be greater than m∠T, it doesn't have to be.  (See examples 1 and 2 from option 3.)

So, option 6 does NOT have to be true.

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3. m<CAB = 180 degrees - m<EAC

4. Equation 1: m<CAB = m<EAF = 119 degrees

5. m<EAF = m<EAD + m< DAF

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7. m<EAD = 119 degrees-90 degrees = 29 degrees

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Click on this link to find his work and possibly more information of the answer. Thanks!

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we have 630 one-inch unit cubes and we want to completely fill the rectangular box (unknown dimensions).

If all the cubes are fitted tightly inside rectangular box without living any space, then box volume would be equal to cubes volume.

There are 630 one-inch unit cubes, so volume of cubes = 630 cubic inches.

Now the volume of rectangular box would also be 630 cubic inches.

We know the formula for volume of rectangular box = length × width × height.

So we need to find any three positive integers whose product is 630.

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