Question

What is an equation in slope-intercept form for the line that passes through the points (1,-3) and (3,1)

Answer 1

Step-by-step explanation:

Hey there!

Note: Use double point formula for finding the eqaution which passes through two points.

Given;

The points are; (1,-3) and (3,1).

Use double point formula.

$(y - y1) = \frac{y2 - y1}{x2 - x2} (y - y1)$

Put all values.

$(y + 3) = \frac{1 + 3}{3 - 1} (x - 1)$

Simplify it.

$(y + 3) = \frac{4}{2} (x - 1)$

$y + 3 = 2(x - 1)$

$y + 3 = 2x - 2$

$y = 2x - 2 - 3$

$y = 2x - 5$

Therefore, the eqaution is y = 2x-5.

Alternative:

Steps:

• Find slope using slope formula and use one point formula.
• Simplify in the form of y = mx+c form.

Formula:

• Slope = (y2-y1)/(x2-x1)
• One point formula= (y-y1)= m(x-x1)

The points are; (1,-3) and (3,1).

Now;

Slope= (1- (-3))/(3-1)

= (1+3)/2

= 2

Again;

Using one-point formula.

(y+3) = 2(x-1)

y+3= 2x-2

y = 2x -5

Therefore, the equation is y = 2x-5.

(You can follow up any method you want)

Hope it helps....