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3 years ago

Practice :

Mathematics

1 answer:

inna [77]3 years ago

6 0

Answer:

1)The equation of the Parallel line is 2x -y -4=0

2) The equation of the perpendicular line of the given line x+2y+8=0

Step-by-step explanation:

Step(i):-

Given function f(x) = 2x+3 and passes through (0,-4)

Let y =f(x) = 2x+3

y = 2x+3

⇒ 2x -y +3=0

The equation of the parallel line of the given line 2x - y +k =0

This line is passes through the point (0,-4)

⇒ 2 (0) -(-4)+k=0

4 +k=0

⇒ k =-4

The equation of the Parallel line is 2x -y -4=0

Step(ii):-

Given function f(x) = 2x+3

Let y = 2 x + 3

 2x - y +3=0

The equation of the perpendicular line bx -ay +k=0

The equation of the perpendicular line of the given line -x-2y +k =0

This line is passes through the point (0,-4)

⇒ (0) -2(-4)+k=0

8 +k=0

⇒ k =-8

The equation of the perpendicular line of the given line -x-2y -8 =0

The equation of the perpendicular line of the given line x+2y+8=0

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3 years ago

Read 2 more answers

3. Derek throws a baseball upward from an initial height of 3 ft. The baseball hits the ground after 2 seconds.

mariarad [96]

Answer with Step-by-step explanation:

Since we have given that

Initial height = 3 feet

The baseball hits the ground after 2 seconds

t = 2 seconds

So, final velocity = v = 0

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Initial velocity is given by

$v_0=\dfrac{3}{2}=1.5\ ft/sec$

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As we know that the function of height would be

$h(t)=-16t^2+v_0t+h_0$

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Maximum height at time t:

$t=\dfrac{-b}{2a}=\dfrac{-1.5}{2\times -16}=\dfrac{1.5}{32}\approx 0.05\ seconds$

Maximum height would be

$h(0.05)=-16(0.05)^2+1.5\times 0.05+3=3.035\ ft$

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