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shutvik [7]
3 years ago
10

Plz help me simply algebra problem

Mathematics
1 answer:
Sonja [21]3 years ago
5 0

Answer:

Step-by-step explanation:

a^{m}*a^{n}=a^{m+n}\\\\\frac{a^{m}}{a^{n}}=a^{m-n}

\frac{-9p^{-5}(-7)r^{-7}(-4)p^{-4}}{4p^{-10}3p^{10}4p^{-2}}=\frac{(-9)*(-7)-(-4)*r^{-7}*p^{-5+(-4)}}{4*3*4*p^{-10+10+(-2)}}\\\\=\frac{(-3)*(-7)*(-1)r^{-7}p^{-9}}{1*1*4*p^{-2}}\\\\=\frac{(-21)r^{-7}p^{-9 - (-2)}}{4}\\\\=\frac{-21r^{-7}p^{-9+2}}{4}\\\\=\frac{(-21)r^{-7}p^{-7}}{4}

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Solve the system of equations by elimination.
n200080 [17]

Answer:

Step-by-step explanation:

1. 2x - 9y = 23

2 x = 9 y + 23

y = (2 x)/9 - 23/9

2 x - 9 y - 23 = 0

2. 5x - 3y = -1

5 x + 1 = 3 y

y = (5 x)/3 + 1/3

5 x - 3 y + 1 = 0

I belive that should help you out a bit :D

4 0
3 years ago
Read 2 more answers
A person invest $2,940 in an account tgat earns 4.1% annual intrest. Find when the value of the investment reaches 5,000. If nec
serg [7]

Answer:

13.22

Step-by-step explanation:

were solving for t and we know:

a(t)=p(1+(r/n))^nt

5000=a-the total

2940=p-the starting amount

.041=r-the rate

1=n-compound (annual)

plug this into a graph :

5000=2940(1+(.041/1))^x

and you get : 13.22

7 0
3 years ago
Determine whether the relation is a function. Explain why or why not.
Vitek1552 [10]

This relation is a function. This is because no x value is repeated, so it passes the vertical line test.

Here is an example of where a relation is NOT a function:

{(2, 5), (3, –5), (2, 5), (5, –5)}

Hope this helps!

3 0
3 years ago
Solve the equation 6x +2y = 10 for y in terms of x gives what function?
Nimfa-mama [501]

Answer:

y = - 3x + 5

Step-by-step explanation:

Given

6x + 2y = 10 ( subtract 6x from both sides )

2y = - 6x + 10 ( divide all terms by 2 )

y = - 3x + 5

3 0
3 years ago
Solve the equation.9x^2 + 16 = 0
REY [17]

Step 1

Given;

9x^2+16=0

Required: To solve the equation.

Step 2

Solve the equation

\begin{gathered} 9x^2+16-16=0-16 \\ 9x^2=-16 \\ \frac{9x^2}{9}=\frac{-16}{9} \\ x^2=-\frac{16}{9} \\ \sqrt{x^2}=\pm\sqrt{\frac{-16}{9}} \\ x=\sqrt{-\frac{16}{9}},\:x=-\sqrt{-\frac{16}{9}} \\ x=i\frac{4}{3},\:x=-i\frac{4}{3} \end{gathered}

Answer;

x=\frac{4}{3}i,\text{ -}\frac{4}{3}i

4 0
1 year ago
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