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shutvik [7]
3 years ago
10

Plz help me simply algebra problem

Mathematics
1 answer:
Sonja [21]3 years ago
5 0

Answer:

Step-by-step explanation:

a^{m}*a^{n}=a^{m+n}\\\\\frac{a^{m}}{a^{n}}=a^{m-n}

\frac{-9p^{-5}(-7)r^{-7}(-4)p^{-4}}{4p^{-10}3p^{10}4p^{-2}}=\frac{(-9)*(-7)-(-4)*r^{-7}*p^{-5+(-4)}}{4*3*4*p^{-10+10+(-2)}}\\\\=\frac{(-3)*(-7)*(-1)r^{-7}p^{-9}}{1*1*4*p^{-2}}\\\\=\frac{(-21)r^{-7}p^{-9 - (-2)}}{4}\\\\=\frac{-21r^{-7}p^{-9+2}}{4}\\\\=\frac{(-21)r^{-7}p^{-7}}{4}

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The length of the hypotenuse of a 30-60 -90 triangle is 14 units. what is the length of the short leg
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Rasek [7]
Hey You!

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Solve the system with elimination 4x+3y=1 -3x-6y=3
Nuetrik [128]

Answer:

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If we have the two equations:

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y looks like it might be easy to get rid of, we just have to multiply 4x+3y=1  by 2 and y is gone (as -6y + 6y = 0).

So let's multiply the equation 4x+3y=1  by 2.

2(4x + 3y = 1)\\8x + 6y = 2

Now we can add these equations

8x + 6y = 2\\-3x-6y=3\\

------------------------

5x = 5

Dividing both sides by 5, we get x = 1.

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Hope this helped!

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3 years ago
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