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Dima020 [189]
3 years ago
15

Math Homework help please!

Mathematics
2 answers:
spayn [35]3 years ago
8 0
Answer 9.3

explanation:
(7 4/5 + 5 3/10) = 13.1
13.1 - 3 4/5 = 9.3
Setler [38]3 years ago
5 0
The answer should be (exact number- 93/10) (decimal form- 9.3) (mixed number- 9 3/10)
sorry if i’m incorrect
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If 5/8 of the people in water aerobics class are over age 65 and 1/4 of the people in the class are under age 40,what fraction o
LiRa [457]
I think the answer's 7/8. If you convert 1/4 to 2/8 and add them together, you add 5/8 and 2/8 to get 7/8. 
6 0
3 years ago
Day care centers expose children to a wider variety of germs than the children would be exposed to if they stayed at home more o
Ostrovityanka [42]

Answer:

a) The study is an observational study

b) The proportion of children with significant social activity in children with acute lymphoblastic leukemia is approximately 0.802

The proportion of children with significant social activity in children without acute lymphoblastic leukemia is approximately 0.8565

c) The odds ratio is approximately 0.6780

d) The 95% CI is approximately 0.523 < OR < 0.833

e) i) Yes

ii) Children with more social activity have a higher occurrence of acute lymphoblastic leukemia

Step-by-step explanation:

a) An experimental study is a study in which the researcher adds inputs to the study and then monitors the outcomes

An observational study is one in which the researcher observes risk factors and does not intervene in the process

Therefore, the study is an observational study

b) The proportion of children with significant social activity in children with acute lymphoblastic leukemia is \hat p_1 = 1020/1272 = 85/106 = 0.8\overline {0188679245283} ≈ 0.802

The proportion of children with significant social activity in children without acute lymphoblastic leukemia is \hat p_2 = 5343/6238 ≈ 0.8565

c) We have the following two way table;

\begin{array}{ccc}Lymphoblastic \ Leukemia &With \ Social \ Activity & Without \ Social \ Activity\\With&1020 \ (a)&252 \ (b)\\Without&5343 \ (c)&895 \ (d) \end{array}

The \ odds \ ratio = \dfrac{1,020 \times 895}{5,343 \times 252} \approx 0.6780

The odds ratio ≈ 0.6780

d) The 95% confidence interval for the odds ratio is given as follows;

95 \% \ CI = OR \ \pm \ 1.96 \times \sqrt{\dfrac{1}{a} +\dfrac{1}{b}+\dfrac{1}{c}+\dfrac{1}{d}}

Where;

a = 1020, b = 252, c = 5343, d = 895

Therefore;

95 \% \ CI \approx  0.6780 \ \pm \ 1.96 \times \sqrt{\dfrac{1}{1,020} +\dfrac{1}{252}+\dfrac{1}{5,343}+\dfrac{1}{895}} \approx 0.678 \pm0.155

The 95% CI ≈ 0.523 < OR < 0.833

e) i) Given that the observed Odds Ratio is within the Confidence Interval, therefore, there is an indication that the amount of social activity is associated with acute lymphoblastic leukemia

ii) Based on the proportion of the study findings, children with more social activity have a higher occurrence of acute lymphoblastic leukemia

6 0
3 years ago
Help me with my homework idk how to do it
QveST [7]

Answer:

You have to make an equation

Make everything equal to 180 degrees because a triangle makes 180 degrees

If you need more help I can assist you

Step-by-step explanation:

1.

8 0
3 years ago
ram is half his fathers age now. ten years ago he was one third his fathers age then what are their present ages
NeX [460]

x   -  Ram's age now

Ram is half his father's age now, so his father's age is two times Ram's age:

2x  - Ram's father age now

x - 10   -  Ram's age ten years ago

2x - 10    - Ram's father age ten years ago

ten years ago he was one third his father's age so his father's age was three times Ram's age:

2x - 10 = 3•(x - 10)

2x - 10 = 3x - 30

-10 + 30 = 3x - 2x

20 = x

2x = 2•20 = 40

Answer:

<u>Ram is 20 years old now, Ram's father is 40 years old now.</u>

8 0
3 years ago
Is n=3 a solution?<br><br><br>-21 = <img src="https://tex.z-dn.net/?f=%5Cfrac%7B-63%7D%7Bn%7D" id="TexFormula1" title="\frac{-63
nadezda [96]

Yes. -63 / 3 = -21.

Please consider branliest! ^_^

7 0
3 years ago
Read 2 more answers
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