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Tatiana [17]
3 years ago
5

Match the situation to the most appropriate graph #7

Mathematics
1 answer:
tatuchka [14]3 years ago
4 0
Graph K. This is because the cost of a gallon of milk is not increasing constantly, as in a linear rate, but it has only increased a few times in a year. Therefore, graph K shows that a gallon of milk is a steady, unchanged price, then the cost rises and stays the same, then rises again and stays the same. So, it is not a linear graph because the cost of the milk is not going up at a constant rate.
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What is 4f - 24 + 4f = -8
Lynna [10]

Answer:

F = 2

Step-by-step explanation:

4f-24+4f=-8

collect like terms

8f-24=-8

move constant to the right

8f=-8+24

calculate

8f=16

divide both sides by 8

Answer F = 2

3 0
4 years ago
Given a cube with a volume of 36 cm3, what is the volume of a square pyramid that can fit perfectly inside the cube?
LUCKY_DIMON [66]
Hope you know that formula for volume of a cube is area of base time height 
and volume of a square pyramid is area of base time height divide 3 
- so in this your exercise case we know that area of cube is 36 cm^3 what is area of base time height 
- so this mean that the volume of a square pyramide what can fit perfectly inside the cube will be equal 36/3 = 12 cm^3
5 0
3 years ago
Read 2 more answers
If AB = AC; then B = C if
zloy xaker [14]
A is a square matrix
8 0
2 years ago
Read 2 more answers
3(1 - 2x) &gt; 3 - 6x<br> answer
Vlad1618 [11]

Answer:

It’s is also 6 and 9

Step-by-step explanation:

It’s 6 and 9 cause you divide

7 0
3 years ago
Find the real zeros x4-11x2+18=0
masya89 [10]

Answer:

x=√2, x=-√2, x= 3 and x=-3

Step-by-step explanation:

We need to solve the equation x^4 - 11x^2+18=0

We can replace x^4 = u^2 and x^2 = u

So, the equation will become

u^2 -11u+18 = 0

Factorizing the above equation:

u^2 -9u-2u+18 =0

u(u-9)-2(u-9)=0

(u-2)(u-9)=0

u=2, u=9

As, u = x^2, Putting back the value:

x^2 =2 , x^2 =9

taking square roots:

√x^2 =√2 ,√x^2=√9

x=±√2 , x = ±3

so, x=√2, x=-√2, x= 3 and x=-3

6 0
3 years ago
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