Match the situation to the most appropriate graph #7

Mathematics

1 answer:

tatuchka [14]3 years ago

4 0

Graph K. This is because the cost of a gallon of milk is not increasing constantly, as in a linear rate, but it has only increased a few times in a year. Therefore, graph K shows that a gallon of milk is a steady, unchanged price, then the cost rises and stays the same, then rises again and stays the same. So, it is not a linear graph because the cost of the milk is not going up at a constant rate.

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Sam wants to be named the greatest home run hitter of his baseball league. In the past 5 seasons he has hit 24 , 20, 23, 20, and

DIA [1.3K]

Answer:

B. $\frac{H+108}{6}\geq 22$

Sam must hit at least 24 runs in 6th season to qualify for the home run trophy.

Step-by-step explanation:

Let H be number of runs Sam hits in 6th season.

We have been given that Sam wants to be named the greatest home run hitter of his baseball league. In the past 5 seasons he has hit 24, 20, 23, 20, and 21 home runs, respectively.

Let us find the number of runs scored by Sam adding the number of hits in his past 5 seasons.

$\text{5 season score of Sam}=24+20+23+20+21=108$

We are told that to qualify for the home run trophy he must average at least 22 home runs in 6 seasons. So to qualify this season Sam's average must be greater than or equal to 22.

We can represent this information in an inequality as:

$\frac{H+108}{6}\geq 22$

Let us solve our inequality to find the least number of runs Sam must hit to qualify.

Multiplying both sides of our inequality by 6 we will get,

$6\times \frac{H+108}{6}\geq 6\times22$

$H+108\geq 132$

$H\geq 132-108$

$H\geq 24$

Therefore, Sam must hit at least 24 runs this 6th season to qualify for the home run trophy.

8 0

3 years ago

The table shows the battery lives, in hours, of ten Brand A batteries and ten Brand B batteries.

Tomtit [17]

Answer:

D. Both distributions are skewed left, so the interquartile range is the best measure to compare variability.

Step-by-step explanation:

Plotting the data roughly shows that the data is skewed to the left. In other words, data is skewed negatively and that the long tail will be on the negative side of the peak.

In such a scenario, interquartile range is normally the best measure to compare variations of data.

Therefore, the last option is the best for the data provided.

please mark me brainliest :)

7 0

3 years ago

The mean of a sequence of n numbers is m. If we split the sequence into two sequences of lengths n1 and n2 and compute their mea

Furkat [3]

The mean of a sequence of numbers is the average.

The true statement is: $\mathbf{mn = m_1 \times n_1 + m_2 \times n_2}$