What is the product? Multiple choice options in second screenshot
2 answers:
You might be interested in
Suppose the sides of the big triangle are called m, x and 12+4=16. We have that the big triangle and the small triangle to the right of the shape (sides x,y,12) are similar. We can take then the ratios of correponding sides and know that they will be equal. Thus, we have that 4/y=y/12. Hence, y*y=48. Thus y=
.
Answer:
75% confidence interval is 91.8±16.66. That is between 75.1 and 108.5 pounds.
Step-by-step explanation:
The question is missing. It is as follows:
Adult wild mountain lions (18 months or older) captured and released for the first time in the San Andres Mountains had the following weights (pounds): 69 104 125 129 60 64
Assume that the population of x values has an approximately normal distribution.
Find a 75% confidence interval for the population average weight μ of all adult mountain lions in the specified region. (Round your answers to one decimal place.)
75% Confidence Interval can be calculated using M±ME where
- M is the sample mean weight of the wild mountain lions (
)
- ME is the margin of error of the mean
And margin of error (ME) of the mean can be calculated using the formula
ME= where
- t is the corresponding statistic in the 75% confidence level and 5 degrees of freedom (1.30)
- s is the standard deviation of the sample(31.4)
- N is the sample size (6)
Thus, ME= ≈16.66
Then 75% confidence interval is 91.8±16.66. That is between 75.1 and 108.5
The surface area of the first figure is 160.
The net of the second figure is attached, and the surface area is 408.
To find the surface area of the first figure, we find the area of the base:
10*10 = 100
Now we find the area of each of the 4 lateral faces (triangles):
A=1/2bh = 1/2(3)(10) = 15
The total is 100+15(4) = 160
To find the surface area of the second figure, find the area of the bases (triangles):
A=1/2bh = 1/2(6)(8)= 24
The area of the bottom lateral face is 15*6 = 90.
The area of the slanted lateral face is 15*10 = 150.
The area of the vertical lateral face is 15*8 = 120.
Together we have 24(2) + 90 + 150 + 120 = 408.
The net of the second figure is attached, and the surface area is 408.
To find the surface area of the first figure, we find the area of the base:
10*10 = 100
Now we find the area of each of the 4 lateral faces (triangles):
A=1/2bh = 1/2(3)(10) = 15
The total is 100+15(4) = 160
To find the surface area of the second figure, find the area of the bases (triangles):
A=1/2bh = 1/2(6)(8)= 24
The area of the bottom lateral face is 15*6 = 90.
The area of the slanted lateral face is 15*10 = 150.
The area of the vertical lateral face is 15*8 = 120.
Together we have 24(2) + 90 + 150 + 120 = 408.