The slope-point formula of a line:
![y-y_1=m(x-x_1)](https://tex.z-dn.net/?f=y-y_1%3Dm%28x-x_1%29)
We have:
![m=2,\ (-8,\ 1)\to x_1=-8,\ y_1=1](https://tex.z-dn.net/?f=m%3D2%2C%5C%20%28-8%2C%5C%201%29%5Cto%20x_1%3D-8%2C%5C%20y_1%3D1)
Substitute:
![y-1=2(x-(-8))\\\\\boxed{y-1=2(x+8)}](https://tex.z-dn.net/?f=y-1%3D2%28x-%28-8%29%29%5C%5C%5C%5C%5Cboxed%7By-1%3D2%28x%2B8%29%7D)
Answer:
The two numbers are 40, and 27.
Explanation:
Since there are only two numbers, with two different aspects, you can just make
a system, and solve.
A sum of two numbers adding up to 67 can be modeled by: x + y = 67.
A difference of those same two numbers being 13 can be modeled by: x – y = 13.
You can add the two equations together to eliminate the y value because the -y and y will cancel out:
x + y = 67.
+ x – y = 13.
And you get: 2x = 80.
Now to find x, just divide by 2 on both sides to cancel out the coefficient of 2 in 2x:
2x = 80
÷2 ÷2
x = 40.
So the first number is 40.
Since we know the first number, we can immediately find the other number by substituting it into the first equation.
x = 40 → x + y = 67
(40) + y = 67
-40. -40
Subtract from both sides to cancel the constant terms.
Then you will get that y or the second number is y = 27.
This is true because 40 + 27 = 67, and 40 - 27 = 13.
Here is the answer to your question
When given two end points of a segment say for example (X1,Y1) and (X2,Y2) to get the midpoint of the line or the segment we use the formula,
midpoint =( (X1+X2)/2 , (Y1+Y2)/2 )
therefore in our case the midpoint is (0,1)
hence, (-2 + X2)/ 2 = 0, thus X2 = 2
and (3 + Y2)/ 2= 1 , thus Y2 = -1
Therefore the other end point will be (2,-1). Thus none of the above paper can be used as the other end point.
Answer:
- 24x + 9
Step-by-step explanation:
Differentiate each term using the power rule
( a
) = na![x^{n-1}](https://tex.z-dn.net/?f=x%5E%7Bn-1%7D)
Given
f(x) = - 12x² + 9x, then
f'(x) = (2 × - 12)x + (9 × 1)
= - 24x + 9