Answer:
-10x^2 +9+8x^2-5x+7=-2x^2-5x+16
Answer:
Step-by-step explanation:
y = sin(t^2)
y' = 2tcos(t^2)
y'' = 2cos(t^2) - 4t^2sin(t^2)
so the equation become
2cos(t^2) - 4t^2sin(t^2) + p(t)(2tcos(t^2)) + q(t)sin(t^2) = 0
when t=0, above eqution is 2. That is, there does not exist the solution. so y can not be a solution on I containing t=0.
It’s the third one I believe try that
Answer:
3.149
Step-by-step explanation:
that is just the number pi never ends but in most math classes 3.149 is all yoi need
69 ghcfhhggghjjohufdhhdjc
