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rjkz [21]
3 years ago
14

Jackrabbits are capable of reaching speeds up to 40 miles per hour how fast is this per second

Mathematics
2 answers:
Mumz [18]3 years ago
5 0

Answer: 59 feet per second

Step-by-step explanation:

I'm assuming you made a typo and meant to type 'how many feet per second'

The speed of the Jackrabbits is 40 miles per hour.

We know that

1 mile = 5280 feet

1 hour = 3600 seconds

40 miles = (40 × 5280) feet = 211200 feet

211200/3600 = 58.67 feet per second

The speed of the Jackrabbits to the nearest whole number is 59 feet/second.

lara31 [8.8K]3 years ago
3 0

Answer:

59 ps

Step-by-step explanation:

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<h3>Answer: slope = 1/3</h3>

===================================================

Work Shown:

Use the slope formula to get

m = (y2 - y1)/(x2 - x1)

m = (0 - (-3))/(9 - 0)

m = (0 + 3)/(9 - 0)

m = 3/9

m = 1/3

----------------

Basically we subtract the y coordinates, and do the same for the x coordinates as well (subtract in the same order). Afterward, divide the two results. Reduce the fraction as much as possible.

A slope of 1/3 means we move up 1 unit each time we move to the right 3 units.

The slope being positive means the line goes uphill as you read from left to right.

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3 years ago
Show work<br> please! this is due tmr
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Answer:

-120

Step-by-step explanation:

subtract 45 to both sides

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multiply by 8 on both sides.

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2 years ago
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The area of the circle is 64pie cm. What is the radius in cm?
Vinil7 [7]

Answer: 8 centimeters

Step-by-step explanation: To find the radius of the circle, remember that the formula for the area of a circle is πr² and since we're given that the area of our circle is 64π, we can set up the equation 64π = πr².

To solve for <em>r</em>, we first divide both sides of the equation by π.

On the left side, the π's cancel and we're left with 64 and on the right side, the π's cancel and we're left with r².

So we have 64 = r².

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4. Find the area of the following composite figure.
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Step-by-step explanation:

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Match each series with the equivalent series written in sigma notation
PIT_PIT [208]

Answer:

3 + 12 + 48 + 192 + 768 = \sum\limits^4_{n=0} 3 * 4^n

4 + 32 + 256 + 2048 + 16384 = \sum\limits^4_{n=0} 4 * 8^n

2 + 6 + 18 + 54 + 162 = \sum\limits^4_{n=0} 2* 3^n

3 + 15 + 75 + 375 + 1875 = \sum\limits^4_{n=0} 3* 5^n

Step-by-step explanation:

Given

See attachment for complete question

Required

Match equivalent expressions

Solving (a):

3 + 12 + 48 + 192 + 768

The expression can be written as:

3 \to 3*4^{0 --- 0

12 \to 3 * 4^{1 ---- 1

48 \to 3 * 4^{2 --- 2

192 \to 3 * 4^{3 ---- 3

768 \to 3 * 4^{4 ---- 4

For the nth term, the expression is:

Term = 3 * 4^{n ---- n

So, the summation is:

3 + 12 + 48 + 192 + 768 = \sum\limits^4_{n=0} 3 * 4^n

Solving (b):

4 + 32 + 256 + 2048 + 16384

The expression can be written as:

4 \to 4 * 8^0 --- 0

32 \to 4 * 8^1 ---- 1

256 \to 4 * 8^2 --- 2

2048 \to 4 * 8^3 ---- 3

16384 \to 4 * 8^4 ---- 4

For the nth term, the expression is:

Term \to 4 * 8^n ---- n

So, the summation is:

4 + 32 + 256 + 2048 + 16384 = \sum\limits^4_{n=0} 4 * 8^n

Solving (c):

2 + 6 + 18 + 54 + 162

The expression can be written as:

2 \to 2 * 3^0 --- 0

6 \to 2 * 3^1 ---- 1

18 \to 2 * 3^2 --- 2

54 \to 2 * 3^3 ---- 3

162 \to 2 * 3^4 ---- 4

For the nth term, the expression is:

Term \to 2 * 3^n ---- n

So, the summation is:

2 + 6 + 18 + 54 + 162 = \sum\limits^4_{n=0} 2* 3^n

Solving (d):

3 + 15 + 75 + 375 + 1875

The expression can be written as:

3 \to 3 * 5^0 --- 0

15 \to 3 * 5^1 ---- 1

75 \to 3 * 5^2 --- 2

375 \to 3 * 5^3 ---- 3

1875 \to 3 * 5^4 ---- 4

For the nth term, the expression is:

Term \to 3 * 5^n ---- n

So, the summation is:

3 + 15 + 75 + 375 + 1875 = \sum\limits^4_{n=0} 3* 5^n

5 0
2 years ago
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