Answer:
x = 12
Step-by-step explanation:
20/35 and 21/35. The common denominator is 35.
Answer: the probability that a randomly selected Canadian baby is a large baby is 0.19
Step-by-step explanation:
Since the birth weights of babies born in Canada is assumed to be normally distributed, we would apply the formula for normal distribution which is expressed as
z = (x - µ)/σ
Where
x = birth weights of babies
µ = mean weight
σ = standard deviation
From the information given,
µ = 3500 grams
σ = 560 grams
We want to find the probability or that a randomly selected Canadian baby is a large baby(weighs more than 4000 grams). It is expressed as
P(x > 4000) = 1 - P(x ≤ 4000)
For x = 4000,
z = (4000 - 3500)/560 = 0.89
Looking at the normal distribution table, the probability corresponding to the z score is 0.81
P(x > 4000) = 1 - 0.81 = 0.19
Answer:
D) no solution
Step-by-step explanation:
1/ (x-2) + 1/(x+2) = 4/(x^2-4)
x cannot equal 2 or -2 since that would make our fractions equal 1/0 or be undefined
Factor the term on the right
1/ (x-2) + 1/(x+2) = 4/(x-2)(x+2)
Multiply both sides by (x-2) (x+2)
(x-2) (x+2) (1/ (x-2) + 1/(x+2)) = 4/(x-2)(x+2)*(x-2) (x+2)
Distribute
x+2 + (x-2) = 4
Combine like terms
2x = 4
Divide by 2
2x/2 = 4/2
x =2
But this is not a possible solution since that is not in the domain
