All categories

3 years ago

the perimeter of a rectangle is 15x+17y if the length is 7/2x +7y then find the width of the rectangle

Mathematics

1 answer:

kirza4 [7]3 years ago

4 0

Answer:

it is 15

Step-by-step explanation:

it just is cause i am that good

You might be interested in

How many counters would you place in the five frame to show the number

Leviafan [203]

Assuming the five frame is for the number five (5) then place 5 counters in the frame.

7 0

3 years ago

When placed in liquid nitrogen, a chemical changes in temperature by -4.8°C

Lena [83]

Answer:

-2.4

Step-by-step explanation:

3 0

3 years ago

What is the property that allows you move the parentheses in a problem and still get the same answer

Gnoma [55]

<span> The </span>associative property<span> states that you can add or multiply regardless of how the numbers are grouped. By"grouped" we mean 'how you use parenthesis'. In other words, if you are adding or multiplying it does not matter where you put the parenthesis</span>

3 0

3 years ago

Complete the equation of the line through (-10,3) and (-8,-8)

Alina [70]

Answer: 2y + 11x = -104

Step-by-step explanation:

The formula for calculating equation of line given two points is :

$\frac{y-y_{1}}{x-x_{1}}$ = $\frac{y_{2}-y_{1}}{x_{2}-x_{1}}$

$x_{1}$ = -10

$x_{2}$ = -8

$y_{1}$ = 3

$y_{2}$ = -8

substituting the values into the formula , we have :

$\frac{y-3}{x-(-10)}$ = $\frac{-8-3}{-8-(-10)}$

$\frac{y - 3}{x + 10}$ = $\frac{-11}{2}$

2(y - 3 ) = -11 ( x +10 )

2y - 6 = -11x - 110

2y + 11x = -110 + 6

2y + 11x = -104

Therefore : the equation of the line in standard form is 2y + 11x = -104

8 0

3 years ago

Using Pythagorean inequalities, determine which of the following sets of values can represent the lengths of the sides of an acu

seropon [69]

Answer:

Step-by-step explanation:

$a,\ b,\ c-\text{sides of a triangle}\\\\\text{If}\ a\leq b< c\ \text{and}\ a^2+b^2=c^2,\ \text{then it's the lengths of the sides of a right triangle}\\\\\text{If}\ a\leq b\leq c\ \text{and}\ a^2+b^2>c^2,\ \text{then it's the lengths of the sides of a acute triangle}\\\\\text{If}\ a\leq b< c\ \text{and}\ a^2+b^2$

$\text{Triangle condition:}\\\text{That each side has to be shorter than the sum of the other two sides}\\\text{and longer than their difference.}\\\\\text{If}\ a\leq b\leq c,\ \text{then}\ a+b>c.$

$--------------------------\\a.\\a=1,\ b=2,\ c=3\\\\a+b=1+2=3=c\\\\\text{These are not the lengths of the sides of the triangle.}\\----------------------------\\b.\\a=6,\ b=8,\ c=10\\\\a+b=6+8=14>10=c\qquad OK\\\\a^2+b^2=6^2+8^2=36+64=100\\\\c^2=10^2=100\\\\a^2+b^2=c^2\\\\\text{It's the right triangle.}\\----------------------------$

$c.\\a=6,\ b=7,\ c=8\\\\a+b=6+7=13>8\qquad OK\\\\a^2+b^2=6^2+7^2=36+49=85\\\\c^2=8^2=64\\\\a^2+b^2>c^2\\\\\text{It's the acute triangle.}\\----------------------------\\d.\\a=4,\ b=6,\ c=10\\\\a+b=4+6=10=c\\\\\text{These are not the lengths of the sides of the triangle.}$

6 0

3 years ago