-2x + 11 + 6x = ?????

F-7/g=h solve for f What are the steps to solve for f?

nexus9112 [7]

$\dfrac{f-7}{g}=h\ \ \ \ |\text{multiply both sides by g}\neq0\\\\f-7=gh\ \ \ \ |\text{add 7 to both sides}\\\\\boxed{f=gh+7}$

4 0

3 years ago

Write an equation to describe the cost of the number of kilowatt-hours of electricity from 1,001 to 1,500 answers

Taya2010 [7]

1001x+1500=y. This is ur equation

3 0

3 years ago

Which pair of measurements is not equivalent? 6,000 mL, 6 L 9500 mL, 9.5 L 4.5 L, 450 mL 0.3 L, 300 mL

dalvyx [7]

4.5l and 450ml are the pair of measurements which is not equivalent

Solution:

Let us solve each pair of measurements to find which is not equivalent

first pair: 6000 ml and 6 L

To compare both quantities, they must be in same units. Let us convert them into same units

we know that 1 liter = 1000 milliliter

Hence 6 liter = 6000 milliliter

Hence both are equivalent. This pair is correct

Second pair: 9500 ml and 9.5L

$9.5L = 9.5 \times 1000 = 9500ml$

Hence both are equivalent. This pair is correct

Third pair: 4.5L and 450 ml

$4.5l = 4.5 \times 1000 = 4500 ml$

Both are not equivalent

Fourth pair: 0.3 L and 300ml

$0.3l = 0.3 \times 1000 = 300ml$

Hence both are equivalent. This pair is correct

Thus 4.5l and 450ml are not equivalent

6 0

4 years ago

Solve the inequality- 5/2(3x+4)<6-3x. Show your work.

DochEvi [55]

Answer:

x < -8/21

Step-by-step explanation:

Step 1: Simplify both sides of the equation.

$(\frac{5}{2} * 3x) + (\frac{5}{2} * 4) < -3x + 6$
$\frac{15}{2}x + 10 < -3x + 6$

Step 2: Add 3x to both sides.

$\frac{15}{2}x + 10 + 3x < -3x + 6 + 3x$
$\frac{21}{2}x + 10 < 6$

Step 3: Subtract 10 from both sides.

$\frac{21}{2}x + 10 - 10 < 6 - 10$
$\frac{21}{2}x < -4$

Step 4: Multiply both sides by 2/21.

$\frac{21}{2}x * \frac{2}{21} < -4 * \frac{2}{21}$ $x < -\frac{8}{21}$

Therefore, the answer is x < -8/21.

6 0

3 years ago

The value of China's exports of automobiles and parts (in billions of dollars) is approximately f(x)=1.8208e.^3387x, where x = 0

EleoNora [17]

Answer:

This was occur sometimes in year 2002.4

Step-by-step explanation:

* Lets explain how to solve the problem

- The value of China's exports of automobiles and parts

(in billions of dollars) is approximately f(x) = 1.8208 e^(0.3387 x)

# You must pay attention about the function is already calculated in

billions dollars so you will not multiply the value of f(x) by 10^9 to

change it to billions

∵ The value of x = 0 at 1998

- Remember that e^(0) = 1

∴ f(0) = 1.8208 e^(0) = 1.8208 billion dollars

- You need to calculate the year that the export reaches 8 billion

∵ f(x) = 1.8208 e^(0.3387 x)

∵ f(x) = 8 billion

∴ 8 = 1.8208 e^(0.3387 x)

- Divide both sides by 1.8208

∴ 4.393673111 = e^(0.3387 x)

- Insert ㏑ in both sides

∴ ㏑(4.393673111) = ㏑[e^(0.3387 x)]

- Remember ㏑(e^n) = n ㏑(e), ㏑(e) = 1, then ㏑(e^n) = n

∴ ㏑(4.393673111) = 0.3387 x

- Divide both sides by 0.3387

∴ x = ㏑(4.393673111) ÷ 0.3387

∴ x = 4.37 ≅ 4.4

- Lets add the number of years to 1998

∴ The year is 1998 + 4.4 = 2002.4

∴ This was occur sometimes in year 2002.4

5 0

3 years ago