The greatest common factor in this situation is 9 so you could factor out 9 and get 9(7+9) you can check this answer by multiplying both numbers by the number on the outside of the parenthesis.

hope this helps mark brainliest please

5 0

3 years ago

The door on a model building is 10 centimeters tall. The door on the actual building is 3 meters tall.

Alinara [238K]

To find the scale, first and foremost you should convert the length to cm:

3 meters = 300 cm, hence the scale of the model is 10/300 = 1/30

5 0

4 years ago

If the shaded area is 23cm^2, then what is the smallest possible value of the inner area?

bagirrra123 [75]

Answer:

I suspect it can = 0 when the roots are solved for.

x = 10.44 which is the only positive root. There is another one, but I think it gives a minus number for the white area.

Step-by-step explanation:

There are two areas that are possible given the dimensions of the two rectangles. The trick is to find both of them. and compare.

Step One

Find the area of the inside rectangle (unshaded area)

Area = (2x - 1)*x Use the distributive property to find the area

Area = 2x^2 - x

Step Two

Find the area of the outside of the frame

Area = (x + 5)(x + 3) Remove the brackets using FOIL

Area = x^2 + 5x + 3x + 15

Area = x^2 + 8x + 15

Step Three

Find the area of the shaded region

Area shaded = x^2 + 8x + 15 – (2x^2 – x) Remove the brackets

Area shaded = x^2 + 8x + 15 – 2x^2 + x Combine like terms

Area shaded = x^2 + 9x + 15 - 2x^2

Area shaded = -x^2 + 9x + 15

Step Four

Find the roots of the quadratic.

a = -1

b = 9

c = 15

Using the quadratic formula, and substituting for a b and c, we get

$\text{x = }\dfrac{ -b \pm \sqrt{b^{2} - 4ac } }{2a}$

$\text{x = }\dfrac{ -9 \pm \sqrt{9^{2} - 4*(-1)(15 } }{2(-1)}$

$\text{x = }\dfrac{ -9 \pm \sqrt{81 + 4*(1)(15 } }{2(-1)}$

There is only 1 value that works for this problem and that is when x = 10.44

4 0

4 years ago