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Dimas [21]
3 years ago
10

Select the correct answer. Alice and Amy decide to meet at a party. From a corner of the party hall, Amy spots Alice at the corn

er of the hall diagonally opposite her. If the party hall is a rectangle that measures 100 feet by 60 feet, what is the shortest distance Amy has to walk to reach Alice? Round your answer to the nearest foot.
A. 40 feet B. 80 feet C. 117 feet D. 160 feet
Mathematics
1 answer:
Katena32 [7]3 years ago
7 0
Just subtract 100 feet by 60 feet, you will get 40. A.40
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A display case of DVDs are marked 19 for $10. If Larry has $50, how many DVDs can Larry get? (Assume no tax or other fees.)
Delicious77 [7]

Answer:

95

Step-by-step explanation:

19 DVDs for 10 dollars and he has 50 dollars well 50 dollars is just 5 groups of 10 so just 19 x 5 = 95

5 0
2 years ago
PLEASE HELP WILL MARK BRAINLIEST!!!!!! Base the question off this info: An experienced cashier at a grocery store takes 2 second
Vesna [10]
You need to use basic algebra for this.
For this I’ll use o as the items and p for the payment. First you need to find out how long it took for all the items to scan, so if it took each item 2 seconds to be scanned you need to times the total number of items (o) by two e.g. o x 2 = 62 items times two seconds which is equivalent to 62 seconds (1.02 minutes) after this step you need to minus the total time it took to scan the items for the transaction time (2 minutes) e.g. 2.00 - 1.02 = 2.58 minutes.

Hope this helped :)
3 0
3 years ago
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A women spent two thirds of her money. She lost two thirds of the remainder and then had $4 left. How much money did she start w
liq [111]
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3 years ago
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From a window 20 feet above the ground, the angle of elevation to the top of a building across
Nikitich [7]

Answer: The answer is 381.85 feet.

Step-by-step explanation:  Given that a window is 20 feet above the ground. From there, the angle of elevation to the top of a building across  the street is 78°, and the angle of depression to the base of the same building is 15°. We are to calculate the height of the building across the street.

This situation is framed very nicely in the attached figure, where

BG = 20 feet, ∠AWB = 78°, ∠WAB = WBG = 15° and AH = height of the bulding across the street = ?

From the right-angled triangle WGB, we have

\dfrac{WG}{WB}=\tan 15^\circ\\\\\\\Rightarrow \dfrac{20}{b}=\tan 15^\circ\\\\\\\Rightarrow b=\dfrac{20}{\tan 15^\circ},

and from the right-angled triangle WAB, we have'

\dfrac{AB}{WB}=\tan 78^\circ\\\\\\\Rightarrow \dfrac{h}{b}=\tan 15^\circ\\\\\\\Rightarrow h=\tan 78^\circ\times\dfrac{20}{\tan 15^\circ}\\\\\\\Rightarrow h=361.85.

Therefore, AH = AB + BH = h + GB = 361.85+20 = 381.85 feet.

Thus, the height of the building across the street is 381.85 feet.

8 0
3 years ago
2.
Fantom [35]

Answer:

the mode remains the same

Step-by-step explanation:

42 is outlier.

mod is the most repetitive number of a number string, and outlier does not change it.

the mode remains the same.

7 0
3 years ago
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