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Tom [10]
3 years ago
11

Plzz helpp guys

Mathematics
1 answer:
Kitty [74]3 years ago
6 0

Answer:

y = 1500(0.024)^t

Step-by-step explanation:

Given

a = 1500km -- initial area

b = 2.4\% -- rate

t = time --- (years)

Required

Represent as an exponential function

An exponential function has the form:

y = ab^t

Where

a = initial\ value

b = rate and b \ne 1

t= time

Substitute values for a and b, we have:

y = 1500 * (2.4\%)^t

Convert percentage to decimal

y = 1500 * (0.024)^t

y = 1500(0.024)^t

Hence, the exponential function that represents the scenario is: y = 1500(0.024)^t

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A caterpillar started at point (−2.5, −5.5) on a coordinate plane. She crawled in a straight line through the origin to point (4
alexgriva [62]

Answer:

The value of y is 99

Step-by-step explanation:

we know that

A relationship between two variables, x, and y, represent a proportional variation if it can be expressed in the form y/x=k or y=kx

In a proportional relationship the constant of proportionality k is equal to the slope m of the line and the line passes through the origin

In this problem the line passes through the origin

therefore

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3 years ago
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Look at the figure. If m/_ L= 58, find /_ LKJ
kompoz [17]

Answer:

64°

Step-by-step explanation:

KJ = KL, KM is common, and ∠JKM = ∠LKM, so the triangles are congruent.

∴ ∠ J = ∠L = 58°

The three angles of a triangle add up to 180°.

 ∠J + ∠L + ∠LKJ = 180°

58° + 58° + ∠LKJ = 180°

        116° + ∠LKJ = 180°

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The percent defective for parts produced by a manufacturing process is targeted at 4%. The process is monitored daily by taking
vladimir2022 [97]

Answer:

A sample of 767 is needed.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

The margin of error is given by:

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

For this problem, we have that:

14 defectives out of 160, so \pi = \frac{14}{160} = 0.0875

95% confidence level

So \alpha = 0.05, z is the value of Z that has a pvalue of 1 - \frac{0.05}{2} = 0.975, so Z = 1.96.

How many units would have to be sampled to be 95% confident that you can estimate the fraction of defective parts within 2% of the percentage?

We would need a sample of n.

n is fround when M = 0.02.  So

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

0.02 = 1.96\sqrt{\frac{0.0875*0.9125}{n}}

0.02\sqrt{n} = 1.96\sqrt{0.0875*0.9125}

\sqrt{n} = \frac{1.96\sqrt{0.0875*0.9125}}{0.02}

(\sqrt{n})^2 = (\frac{1.96\sqrt{0.0875*0.9125}}{0.02})^2

n = 766.8

Rounding up

A sample of 767 is needed.

3 0
3 years ago
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