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2 years ago

Need help! only have today till I turn in!

Mathematics

2 answers:

12345 [234]2 years ago

7 0

Answer:

yes

Step-by-step explanation:

allsm [11]2 years ago

6 0

(y1-y2)/(x1-x2)=(10-6)/(8-0) OR (6-10)/(0-8)
= 0.5
In that case you now know. The answer to the first blank (coefficient of x)
To find the y intercept (the second blank), which I will call c, you can use either pair of the coordinates and substitute them in the equation together with the gradient you found previously.
If you choose to sub in (0,6) and since gradient=0.5,
Then: 6=0.5(0) + c
therefore, c=6
Likewise, if you choose to sub in (8,10)
Then: 10=0.5(8) + c
Therefore, c also equals to 6
So in conclusion the gradient of the slop is 0.5 and the y intercept is 6
The linear function will be: y=0.5x + 6

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3 years ago

Teresa is building a scale model of the JP Morgan chase Tower in Houston.In her scale model, 1.5 inches represents 61 meters. Si

Jet001 [13]

Answer:

Teresa should build 7.5 inches model.

Step-by-step explanation:

Consider the provided information.

Teresa is building a scale model of the JP Morgan chase Tower in Houston.

Her scale model, 1.5 inches represents 61 meters.

The actual building is 305 meters tall,

First find how many 61's are there in 305.

For this divide 305 by 61.

$\frac{305}{61}= 5$

Actual building is 5 times taller than 61. Thus the model should be 5 times taller than 1.5.

multiply 1.5 with 5 gives us:

$1.5\times 5=7.5$

Hence, Teresa should build 7.5 inches model.

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3 years ago

A food packet is dropped from a helicopter and is modeled by the function f(x) = −15x2 + 6000. The graph below shows the height

melisa1 [442]

General Idea:

Domain of a function means the values of x which will give a DEFINED output for the function.

Applying the concept:

Given that the x represent the time in seconds, f(x) represent the height of food packet.

Time cannot be a negative value, so

$x\geq 0$

The height of the food packet cannot be a negative value, so

$f(x)\geq 0$

We need to replace $-15x^2+6000$ for f(x) in the above inequality to find the domain.

$-15x^2+6000\geq 0 \; \; [Divide \; by\; -15\; on\; both\; sides]\\ \\ \frac{-15x^2}{-15} +\frac{6000}{-15} \leq \frac{0}{-15} \\ \\ x^2-400\leq 0\;[Factoring\;on\;left\;side]\\ \\ (x+200)(x-200)\leq 0$

The possible solutions of the above inequality are given by the intervals $(-\infty , -2], [-2,2], [2,\infty )$ . We need to pick test point from each possible solution interval and check whether that test point make the inequality $(x+200)(x-200)\leq 0$ true. Only the test point from the solution interval [-200, 200] make the inequality true.