2 years ago

Please help me if you know the answer

1 answer:

viva [34]2 years ago

4 0

Dependent variable is the one on the y axis. So for this problem, it’s money collected.

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mixas84 [53]

Answer:

translation.........

4 0

2 years ago

EleoNora [17]

Answer:

The probability that a randomly selected passenger car gets more than 37.3 mpg is 0.1587.

Step-by-step explanation:

Let the random variable <em>X</em> represent the miles-per-gallon rating of passenger cars.

It is provided that $X\sim N(\mu=33.8,\ \sigma^{2}=3.5^{2})$ .

Compute the probability that a randomly selected passenger car gets more than 37.3 mpg as follows:

$P(X>37.3)=P(\frac{X-\mu}{\sigma}>\frac{37.3-33.8}{3.5})$

$=P(Z>1)\\\\=1-P(Z$

Thus, the probability that a randomly selected passenger car gets more than 37.3 mpg is 0.1587.

7 0

2 years ago

aksik [14]

Answer:

I think 3

Step-by-step explanation:

i think 3

for real this time

3 0

2 years ago

sdas [7]

202 + 8 = 210
210 + 8 = 218
218 + 8 = 226

The number is 226.

5 0

3 years ago

Dafna11 [192]

Answer: The answer is (y^2) to the power of -0.5

Step-by-step explanation:

8 0

2 years ago