Answer:
![-0.048](https://tex.z-dn.net/?f=-0.048%3CP_1-P_2%3C0.036)
Do not reject ![H_0:P_1-P_2=0](https://tex.z-dn.net/?f=H_0%3AP_1-P_2%3D0)
Step-by-step explanation:
From the question we are told that
Sample size ![n_1=350](https://tex.z-dn.net/?f=n_1%3D350)
Sample size ![n_2=250](https://tex.z-dn.net/?f=n_2%3D250)
Sample proportion 1 ![\hat P= \frac{25}{350} =>0.07](https://tex.z-dn.net/?f=%5Chat%20P%3D%20%5Cfrac%7B25%7D%7B350%7D%20%3D%3E0.07)
Sample proportion 2 ![\hat P= \frac{19}{250} =>0.076](https://tex.z-dn.net/?f=%5Chat%20P%3D%20%5Cfrac%7B19%7D%7B250%7D%20%3D%3E0.076)
95% confidence interval
Generally for 95% confidence level
Level of significance
![\alpha = 1-0.95=>0.05](https://tex.z-dn.net/?f=%5Calpha%20%3D%201-0.95%3D%3E0.05)
![\alpha /2=\frac{0.05}{2} =>0.025](https://tex.z-dn.net/?f=%5Calpha%20%2F2%3D%5Cfrac%7B0.05%7D%7B2%7D%20%3D%3E0.025)
Therefore
![Z_a_/_2=1.96](https://tex.z-dn.net/?f=Z_a_%2F_2%3D1.96)
Generally the equation for confidence interval between
is mathematically given as
![(\hat P_1-\hat P_2)\pm Z_a_/_2\sqrt{\frac{\hat P_1(1-\hat P_1)}{n_1}+\frac{\hat P_2(1-\hat P_2)}{n_2} }](https://tex.z-dn.net/?f=%28%5Chat%20P_1-%5Chat%20P_2%29%5Cpm%20Z_a_%2F_2%5Csqrt%7B%5Cfrac%7B%5Chat%20P_1%281-%5Chat%20P_1%29%7D%7Bn_1%7D%2B%5Cfrac%7B%5Chat%20P_2%281-%5Chat%20P_2%29%7D%7Bn_2%7D%20%20%7D)
![(0.07-0.076)\pm 1.96\sqrt{\frac{0.07(1-0.07)}{350}+\frac{0.076(1-0.076)}{250} }](https://tex.z-dn.net/?f=%280.07-0.076%29%5Cpm%201.96%5Csqrt%7B%5Cfrac%7B0.07%281-0.07%29%7D%7B350%7D%2B%5Cfrac%7B0.076%281-0.076%29%7D%7B250%7D%20%20%7D)
![(0.07-0.076)\pm 1.96\sqrt{4.66896*10^-^4 }](https://tex.z-dn.net/?f=%280.07-0.076%29%5Cpm%201.96%5Csqrt%7B4.66896%2A10%5E-%5E4%20%20%7D)
![(-0.006)\pm 0.042](https://tex.z-dn.net/?f=%28-0.006%29%5Cpm%200.042)
![(-0.006)+ 0.042=>0.036](https://tex.z-dn.net/?f=%28-0.006%29%2B%200.042%3D%3E0.036)
Therefore
Confidence interval is
![-0.048](https://tex.z-dn.net/?f=-0.048%3CP_1-P_2%3C0.036)
Conclusion
Given the confidence interval has zero
Therefore do not reject ![H_0:P_1-P_2=0](https://tex.z-dn.net/?f=H_0%3AP_1-P_2%3D0)
<h3>The solution is (x, y) = (3, -24)</h3>
<em><u>Solution:</u></em>
<em><u>Given system of equations are:</u></em>
-3x - y = 15 -------- eqn 1
y = -8x ------ eqn 2
We have to find solution of (x, y)
We can solve by substitution method
<em><u>Substitute eqn 2 in eqn 1</u></em>
-3x - (-8x) = 15
-3x + 8x = 15
5x = 15
Divide both sides by 5
<h3>x = 3</h3>
Substitute x = 3 in eqn 2
y = -8(3)
<h3>y = -24</h3>
Thus solution is (x, y) = (3, -24)
Answer:it is neither accurate nor precise
Step-by-step explanation:
Answer:
Minimum total cost = $20550
maximum revenue $44,100
Step-by-step explanation:
Given data:
Production cost $5.55 per unit
Fixed cost = $15000 per month
Price, p = 42-0.01 q
where. q represent number of unit produced
revenue can be wriiten as
p.q = 42q - 0.01q^2
1) from information 1000 unit has to produced therefore
total cost = 15000 + 5.55×1000 = $20550
Minimum total cost = $20550
2) Revenue = 42q - 0.01q^2
![\frac{d revenue}{dq} = 42q - 2\times 0.01q = 0](https://tex.z-dn.net/?f=%5Cfrac%7Bd%20revenue%7D%7Bdq%7D%20%3D%2042q%20-%202%5Ctimes%200.01q%20%3D%200)
therefore for maximum revenue q is = 2100
so, maximum revenue ![= 4.2 \times 2100 - 0.01(2100)^2](https://tex.z-dn.net/?f=%3D%20%204.2%20%5Ctimes%202100%20-%200.01%282100%29%5E2)
= $44,100
Dividing any number by zero gives an indeterminate result.
Its C