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irakobra [83]
3 years ago
8

How to solve 3y² + 2y - 8​

Mathematics
2 answers:
Ber [7]3 years ago
6 0
(Y+2) (3y-4) I hope that it’s right
Lyrx [107]3 years ago
3 0

Answer:

(y + 2) (3y - 4)

Step-by-step explanation:

1. 3y^2 + 2y - 8

Rewrite the expression.

2. 3y^2 + 6y - 4y - 8

Factor the expression.

3. 3y(y + 2) - 4(y + 2)

Factor the expression once again.

4. (y + 2) (3y - 4)

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Please help with this graph ‼️
svlad2 [7]
Considering f(x)= y. You find what y value correlates with the x value so f(0)=4 brong that the line with y=4 the x is 0. f(-2)= 2 as the line where x=-2 has y=2
3 0
3 years ago
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Please someone help me
Rainbow [258]

Answer:

Step-by-step explanation:

5)

DG= 60 (whole)

DO= 4x-3 (Part)

OG= 2x+ 21 (Part)

4x-3+ 2x+21= 60

6x+18=60

6x=42

x=7

Using this we can solve for DO and DG

DO= 4*7-3

DO= 25

DG= 2*7+21

DG= 14+ 21= 35

6)

TB is whole

TU is part

UB is part

5x= 4x-1+2x-1

5x=6x-2

x=2

UB= 2*2-1= 4-1= 3

TU= 4*2-1= 8-1= 7

7 0
3 years ago
Given the function f(x) = 4(2)x, Section A is from x = 1 to x = 2 and Section B is from x = 3 to x = 4.
Dmitry [639]

Answer:

Step-by-step explanation:

I'm sure you want your functions to appear as perfectly formed as possible so that others can help you.  f(x) = 4(2)x should be written with the " ^ " sign to denote exponentation:  f(x) = 4(2)^x

                                                                                      f(b) - f(a)

The formula for "average rate of change" is a.r.c. = --------------

                                                                                           b - a

                                    change in function value

This is equivalent to  ---------------------------------------

                                            change in x value

For Section A:  x changes from 1 to 2 and the function changes from 4(2)^1 to  4(2)^2:  8 to 16.  Thus, "change in function value" is 8 for a 1-unit change in x from 1 to 2.  Thus, in this Section, the a.r.c. is:

                 8

               ------ = 8 units    (Section A)

                  1

Section B:  x changes from 3 to 4, a net change of 1 unit:  f(x) changes from

4(2)^3 to 4(2)^4, or 32 to 256, a net change of 224 units.  Thus, the a.r.c. is

        224 units

      ----------------- = 224 units (Section B)

            1 unit

The a.r.c for Section B is 28 times greater than the a.r.c. for Section A.

This change in outcome is so great because the function f(x) is an exponential function; as x increases in unit steps, the function increases much faster (we say "exponentially").

7 0
4 years ago
Kieran’s wallet contains 7 bills: three $5 bills, two $10 bills, one $20 bill, and one $100 bill. If Kieran pulls out two bills
notka56 [123]

Answer:

Exact probability = 1/7

(Approximate probability = 0.142857)

========================================================

Explanation:

There are three 5 dollar bills out of 7 total. The probability of selecting a five dollar bill is 3/7. Let A = 3/7 since we'll use it later.

After the first selection is made, we have 3-1 = 2 five dollar bills left out of 7-1 = 6 bills overall. This is assuming we do not put the first selection back, or replace it with another five dollar bill.

The probability of selecting another five dollar bill is 2/6 = 1/3. Let B = 1/3.

Multiply the values of A and B to get

A*B = (3/7)*(1/3) = (3*1)/(7*3)= 1/7

Note the 3's divide and cancel out.

Using a calculator, 1/7 = 0.142857 approximately

6 0
3 years ago
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