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irakobra [83]
2 years ago
8

How to solve 3y² + 2y - 8​

Mathematics
2 answers:
Ber [7]2 years ago
6 0
(Y+2) (3y-4) I hope that it’s right
Lyrx [107]2 years ago
3 0

Answer:

(y + 2) (3y - 4)

Step-by-step explanation:

1. 3y^2 + 2y - 8

Rewrite the expression.

2. 3y^2 + 6y - 4y - 8

Factor the expression.

3. 3y(y + 2) - 4(y + 2)

Factor the expression once again.

4. (y + 2) (3y - 4)

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Answer:

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Step-by-step explanation:

The root 1 is associated with the factor (x - 1).

The root 1/2 is associated with the factor (x - 1/2), which in turn is equivalent to (2x -1)

The quadratic in question is f(x) = (x - 1)(2x - 1).  To write this in standard form, perform the indicated multiplication:

f(x) = 2x^2 - 2x - x + 1, or f(x) = 2x^2 - 3x + 1

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HELP ME PLEASE!!!!!!! ASAP!!!
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