The answer is D. My dad taught me an easy way to solve those kind of problems.You need to do (60×20)÷100. And since 60 and 20 both have a zero and 100 has 2 zeros, u can cross out all the zeros and just do 6×2 and divide that by 1 and so 20% of 60 is 12. Hope this helped :)
Answer:
∠J = 60°
Step-by-step explanation:
The Law of Cosines tells you ...
j² = k² +l² -2kl·cos(J)
Solving for J gives ...
J = arccos((k² +l² -j²)/(2kl))
J = arccos((14² +80² -74²)/(2·14·80)) = arccos(1120/2240) = arccos(1/2)
J = 60°
_____
<em>Additional comment</em>
It is pretty rare to find a set of integer side lengths that result in one of the angles of the triangle being a rational number of degrees.
Hi there!
The two trapezoids are similar, so we can determine a common scale factor:
OL/UR = NM/TS
9/3 = 6/2
3 = 3
Trapezoid ONML is 3x larger than UTSR, so:
RS = 4, LM = y
3RS = LM
3 · 4 = y = 12.
Find x using the same method:
3UT = ON
3(2x+1) = 4x + 9
6x + 3 = 4x + 9
2x = 6
x = 3.
Answer:
the answer is B
a 3d rectangle slided vertically can produce a 2d rectangle
Consider the suggested option:
1) if in 20 gr. of 50% solution given, then pure salt in this mix is 0.5*20=10 gr., and pure water is 0.5*20=10 gr.
2) after Maya added 5 gr. pure salt is 10+5=15 gr. Total mass of mix is 15(pure salt)+10(pure water)=25 gr.
3) new solution is 15/25=0.6 or 60%.
Answer: 25 gr. of 60% salt solution.