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3 years ago

All values of x 5 ( x + 10 )^2 − 30 = − 5 Plzzzz

Mathematics

1 answer:

Sedaia [141]3 years ago

6 0

I got -7. 76 or rounded to -8. If right can you please mark me brainliest?

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If m // n and n // o and p is a transversal, find the

MakcuM [25]

Answer:

See below.

Step-by-step explanation:

Here is one pair of angle of each type. There are more correct answers.

corresponding angles: <K, <O

alternate interior angles: <N, <P

alternate exterior angles: <I, <S

same-side interior angles: <N, <Q

vertical angles: <P, <R

supplementary angles: <J, <M

8 0

3 years ago

Find the length of the segment indicated. Round your answer to the nearest tenth if necessary.

alukav5142 [94]

Answer:

x=5

Step-by-step explanation:

im so bad at explaining things but i hope this helped

3 0

3 years ago

A superhero recently asked his nemesis how many cats she has. She answered with a riddle: "Five dash sixths of my cats plus tw

pochemuha

1 1/6
I think
Or 2 5/6

3 0

3 years ago

Evaluate the triple integral ∭ExydV where E is the solid tetrahedon with vertices (0,0,0),(5,0,0),(0,9,0),(0,0,4).

Elan Coil [88]

Answer: $\int\limits^a_E {\int\limits^a_E {\int\limits^a_E {xy} } \, dV$ = 1087.5

Step-by-step explanation: To evaluate the triple integral, first an equation of a plane is needed, since the tetrahedon is a geometric form that occupies a 3 dimensional plane. The region of the integral is in the attachment.

An equation of a plane is found with a point and a normal vector. Normal vector is a perpendicular vector on the plane.

Given the points, determine the vectors:

P = (5,0,0); Q = (0,9,0); R = (0,0,4)

vector PQ = (5,0,0) - (0,9,0) = (5,-9,0)

vector QR = (0,9,0) - (0,0,4) = (0,9,-4)

Knowing that cross product of two vectors will be perpendicular to these vectors, you can use the cross product as normal vector:

n = PQ × QR = $\left[\begin{array}{ccc}i&j&k\\5&-9&0\\0&9&-4\end{array}\right]$ $\left[\begin{array}{ccc}i&j\\5&-9\\0&9\end{array}\right]$

n = 36i + 0j + 45k - (0k + 0i - 20j)

n = 36i + 20j + 45k

Equation of a plane is generally given by:

$a(x-x_{0}) + b(y-y_{0}) + c(z-z_{0}) = 0$

Then, replacing with point P and normal vector n:

$36(x-5) + 20(y-0) + 45(z-0) = 0$

The equation is: 36x + 20y + 45z - 180 = 0

Second, in evaluating the triple integral, set limits:

In terms of z:

$z = \frac{180-36x-20y}{45}$

When z = 0:

$y = 9 + \frac{-9x}{5}$

When z=0 and y=0:

x = 5

Then, triple integral is:

$\int\limits^5_0 {\int\limits {\int\ {xy} \, dz } \, dy } \, dx$

Calculating:

$\int\limits^5_0 {\int\limits {\int\ {xyz} \, dy } \, dx$

$\int\limits^5_0 {\int\limits {\int\ {xy(\frac{180-36x-20y}{45} - 0 )} \, dy } \, dx$

$\frac{1}{45} \int\limits^5_0 {\int\ {180xy-36x^{2}y-20xy^{2}} \, dy } \, dx$

$\frac{1}{45} \int\limits^5_0 {90xy^{2}-18x^{2}y^{2}-\frac{20}{3} xy^{3} } \, dx$

$\frac{1}{45} \int\limits^5_0 {2430x-1458x^{2}+\frac{94770}{125} x^{3}-\frac{23490}{375}x^{4} } \, dx$

$\frac{1}{45} [30375-60750+118462.5-39150]$

$\int\limits^5_0 {\int\limits {\int\ {xyz} \, dy } \, dx$ = 1087.5

The volume of the tetrahedon is 1087.5 cubic units.

3 0

3 years ago

the total weight of a shipment of 12 boxes was 2160 pounnds. Each box had the same weight how much did 1 box weigh

Andrei [34K]

1 Box Weighed 180 Pounds, Because 2160 Divided By 12 Is 180. Hope That Helps

4 0

3 years ago