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natulia [17]
3 years ago
9

Shelly and Terrence completed a different number of tasks in a game. Shelly earned 90 points on each task. Terrence's total poin

ts were 20 less than shell's total. The expression below shows Terrence's total points in the game: 90x-20. What does the factor X of the first term of the expressik represent?
Mathematics
2 answers:
oksian1 [2.3K]3 years ago
8 0
X is the number of tasks shelly acomplished and the whole explression (90x) is the total number of points she earned.

Answer:

\boxed{\bf~X~is~the~number~of~tasks~finished~by~Shelly.}



Hope it helped,

Happy homework/ study/ exam!
trapecia [35]3 years ago
7 0
X is the total number of tasks completed by shelle
pls mark it as the brainliest 
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3 years ago
HELP! 7th grade math! GIVE CORRECT ANSWER AND YOU WILL GET BRAINLIEST!!
Ksenya-84 [330]

Answer:

ED = 4 units

Step-by-step explanation:

Observing the figure given to us, we can deduce the following:

=>CE = EA (because point E is the midpoint of CA)

Therefore, if CE = EA = x unit, CA = 2x

=>Also, CD = DB (because point D is the midpoint of CB)

Therefore, if CD = DB = y, CB = 2y

Thus, CA/CE = CB/CD = 2 (2x/x = 2y/y)

Going by the above ration we got comparing the ratio of the corresponding sides of ∆CAB and ∆CED (2:1), we can conclude that ∆CAB ~ ∆CED

Using the ratio of the corresponding sides of ∆CAB to ∆CED = (2:1), measure of segment ED is calculated below:

AB/ED = 2/1

8/ED = 2/1

Cross multiply

8 × 1 = 2 × ED

Divide both sides by 2

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ED = 4 units

3 0
3 years ago
Help please, 30 points reward, i literally have no clue
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The explanation for this is one of my favorite pieces of mathematical reasoning. First, let's thing about distance; what's the shortest distance between two points? <em>A straight line</em>. If we just drew a straight line between A and B, though, we'd be missing a crucial element of the original problem: we also need to pass through a point on the line (the "river"). Here's where the mathemagic comes in.

If we take the point B and <em>reflect it over the line</em>, creating the point B' (see picture 1), we can draw a line straight from A to B' that passes through a point on the line. Notice the symmetry here; the distance from the intersection point to B' is<em> the same as its distance to B</em>. So, if we reflect that segment back up, we'll have a path to B, and because it came from of the line segment AB', we know that it's <em>the shortest possible distance that includes a point on the line</em>.

If we apply this same process to our picture, we see that the line segment AB' crosses the line \ell at the point (1, 1)

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3 years ago
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