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kati45 [8]
3 years ago
10

An isosceles triangle has an angle that measures 118°. Which other angles could be in that isosceles triangle? Choose all that a

pply. a 69° b 31 c 118 d 54​
Mathematics
2 answers:
Rina8888 [55]3 years ago
7 0

Answer: B

Step-by-step explanation:

Anna11 [10]3 years ago
5 0

Answer:

b. 31.

Step-by-step explanation:

The other 2 angles in the triangle are congruent so they are:

(180 - 118) / 2

= 31 degrees.

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63% of US adults opposed to taxes on junk food and soda. You randomly select 10 US adults. Find the probability that the number
WARRIOR [948]

Answer:

a) 0.0008 = 0.08% probability that the number of adults who oppose special tax on junk food and soda is exactly one.

b) 0.9644 = 96.44% probability that the number of adults who oppose special tax on junk food and soda is at least four.

c) 0.7795 = 77.95% probability that the number of adults who oppose special tax on junk food and soda is less than eight.

Step-by-step explanation:

For each adult, there are only two possible outcomes. Either they are opposed to taxes on junk food and soda, or they are not. Each adult is independent of other adults, which means that the binomial probability distribution is used to solve the question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

63% of US adults opposed to taxes on junk food and soda.

This means that p = 0.63

You randomly select 10 US adults.

This means that n = 10

(a) exactly one

This is P(X = 1). So

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 1) = C_{10,1}.(0.63)^{1}.(0.37)^{9} = 0.0008

0.0008 = 0.08% probability that the number of adults who oppose special tax on junk food and soda is exactly one.

(b) at least four

This is

P(X \geq 4) = 1 - P(X < 4)

In which

P(X < 4) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3)

So

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{10,0}.(0.63)^{0}.(0.37)^{10} \approx 0

P(X = 1) = C_{10,1}.(0.63)^{1}.(0.37)^{9} = 0.0008

P(X = 2) = C_{10,2}.(0.63)^{2}.(0.37)^{8} = 0.0063

P(X = 3) = C_{10,3}.(0.63)^{3}.(0.37)^{7} = 0.0285

P(X < 4) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) = 0 + 0.0008 + 0.0063 + 0.0285 = 0.0356

P(X \geq 4) = 1 - P(X < 4) = 1 - 0.0356 = 0.9644

0.9644 = 96.44% probability that the number of adults who oppose special tax on junk food and soda is at least four.

(c) less than eight

This is

P(X < 8) = 1 - P(X \geq 8)

In which

P(X \geq 8) = P(X = 8) + P(X = 9) + P(X = 10)

In which

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 8) = C_{10,8}.(0.63)^{8}.(0.37)^{2} = 0.1529

P(X = 9) = C_{10,1}.(0.63)^{9}.(0.37)^{1} = 0.0578

P(X = 10) = C_{10,2}.(0.63)^{10}.(0.37)^{0} = 0.0098

P(X \geq 8) = P(X = 8) + P(X = 9) + P(X = 10) = 0.1529 + 0.0578 + 0.0098 = 0.2205

P(X < 8) = 1 - P(X \geq 8) = 1 - 0.2205 = 0.7795

0.7795 = 77.95% probability that the number of adults who oppose special tax on junk food and soda is less than eight.

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3 years ago
What is the value of 3 in 23
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3 is in the ones place.  It's value is 3 ones or 3.

2 is in the tens place, so it's value is 2 tens or 20.
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The answer is: -2.6 but if you need the alternative form then I'd also in the picture

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balandron [24]

Answer:

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3 years ago
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 <span>time for airplane = 11 am to 1 pm = 2 hr 
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time for auto = 3 am to 1 pm = 10 hr 
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5 0
3 years ago
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