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Alika [10]
3 years ago
6

HELP PLEASE 50 POINTS!!!! PLZ DON'T GUESS!

Mathematics
2 answers:
Olin [163]3 years ago
6 0

Hey DatGamer13!

Question:

Solve for x

Solution:

Subtract 10 from both sides.

3x^2 + 13x − 10 = 10 − 10

3x^2 + 13x − 10 = 0

Factor left side of equation.

(3x − 2) (x + 5) = 0

Set factors equal to 0.

3x − 2 = 0 or x + 5 = 0

Answer:

x = 2/3 or x = −5

aev [14]3 years ago
5 0

Hey DatGamer13!


Question:


Solve for x


Solution:


Subtract 10 from both sides.


3x^2 + 13x − 10 = 10 − 10


3x^2 + 13x − 10 = 0


Factor left side of equation.


(3x − 2) (x + 5) = 0


Set factors equal to 0.


3x − 2 = 0 or x + 5 = 0


Answer:


x = 2/3 or x = −5


P.S do u play xbox

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98 POINTS! PLEASE HELP! I been stuck on this assignment for over 2 weeks. My teacher gave me a simple explanation when I asked f
Colt1911 [192]

See the attached picture.

  • Create an equation for the volume of the box, find the zeroes, and sketch the graph of the function.

The resulting box has a volume

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because the volume of a box is the product of its width (12-x), length (8-x), and height (x).

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You know right away from the factored form of V(x) that the zeroes are x=0,8,12. (zero product property)

  • sketch the graph of the function

Easy to plot by hand. You know the zeroes, and you can check the sign of V(x) for any values of x between these zeros to get an idea of what the graph of V(x) looks like. See the second attached picture.

Here's what I mean by "check the sign" in case you don't follow. We know V(x)=0 when x=0 and x=8. So we pick some value of x between them, say x=1, and find that

V(1)=1(8-1)(12-1)=7\cdot11=77

which is positive, so V(x) will be positive for any other x between 0 and 8. Similarly we would find that V(x) for x between 8 and 12, and so on.

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It's impossible to answer this without knowing the volume of each marble...

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While this is possible to do by hand, the procedure is tedious (look up "solving the cubic equation"). With a calculator, you'd find three approximate solutions

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The box's dimensions are (x in) x (8-x in) x (12-x in).

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If x\approx7.6398, then 8-x\approx0.3602 and 12-x\approx4.3602.

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