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VikaD [51]
3 years ago
6

What is the slope of the line? y + 5 = 2(x + 1)

Mathematics
1 answer:
VikaD [51]3 years ago
7 0

Answer:

The slope is 2

Step-by-step explanation:

Equation of line is y = mx + b

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The play director spent 190190190 hours preparing for a play. That time included attending 353535 rehearsals that took varying a
dybincka [34]

Answer:

The equation 35x+93\frac{3}{4} =190 gives average time spent on 35 rehearsals.

Step-by-step explanation:

We are supposed to find that what question does the equation 35x+93\frac{3}{4} =190 finds answer of.

We can see that 35x represents time spent on 35 rehearsals and 93\frac{3}{4} is time spent on other responsibilities related to play. The sum of these times equals to total time spent on preparing the play.

Now let us solve our equation step by step.

35x+\frac{375}{4} =190

After subtracting 93\frac{3}{4} hours from 190 hours we will get time spent on 35 rehearsals.

35x =190-\frac{375}{4}

35x =\frac{760-375}{4}

35x =\frac{385}{4}

Time spent on 35 rehearsals is 96.25 hours and we are told that each rehearsal took different amount of time. Dividing 96.25 by 35 we will get average time spent on each rehearsal.

x =\frac{96.25}{35}=2.75  

Therefore, equation 35x+93\frac{3}{4} =190 finds average time spent on 35 rehearsals.


7 0
3 years ago
Read 2 more answers
Which property is shown? 4/5+ -<br> 4/5=0
TEA [102]
This looks like the additive inverse property, because when you add something to its negative counterpart (or its additive inverse), you get 0 as a sum.

Another example would be 2+ (-2) = 0. -2 is the additive inverse for 2.
7 0
3 years ago
Solve the following question
White raven [17]

Answer:

g) u^{4}\cdot v^{-1}\cdot z^{3}, h) \frac{(x+4)\cdot (x+2)}{3\cdot (x-5)}

Step-by-step explanation:

We proceed to solve each equation by algebraic means:

g) \frac{u^{5}\cdot v}{z}\div  \frac{u\cdot v^{2}}{z^{4}}

1) \frac{u^{5}\cdot v}{z}\div  \frac{u\cdot v^{2}}{z^{4}} Given

2) \frac{\frac{u^{5}\cdot v}{z} }{\frac{u\cdot v^{2}}{z^{4}} } Definition of division

3) \frac{u^{5}\cdot v\cdot z^{4}}{u\cdot v^{2}\cdot z}   \frac{\frac{a}{b} }{\frac{c}{d} } = \frac{a\cdot d}{b\cdot c}

4) \left(\frac{u^{5}}{u} \right)\cdot \left(\frac{v}{v^{2}} \right)\cdot \left(\frac{z^{4}}{z} \right)  Associative property

5) u^{4}\cdot v^{-1}\cdot z^{3}   \frac{a^{m}}{a^{n}} = a^{m-n}/Result

h) \frac{x^{2}-16}{x^{2}-10\cdot x + 25} \div \frac{3\cdot x - 12}{x^{2}-3\cdot x -10}

1) \frac{x^{2}-16}{x^{2}-10\cdot x + 25} \div \frac{3\cdot x - 12}{x^{2}-3\cdot x -10} Given

2) \frac{\frac{x^{2}-16}{x^{2}-10\cdot x+25} }{\frac{3\cdot x - 12}{x^{2}-3\cdot x - 10} } Definition of division

3) \frac{(x^{2}-16)\cdot (x^{2}-3\cdot x -10)}{(x^{2}-10\cdot x + 25)\cdot (3\cdot x - 12)}  \frac{\frac{a}{b} }{\frac{c}{d} } = \frac{a\cdot d}{b\cdot c}

4) \frac{(x+4)\cdot (x-4)\cdot (x-5)\cdot (x+2)}{3\cdot (x-5)^{2}\cdot (x-4) } Factorization/Distributive property

5) \left(\frac{1}{3} \right)\cdot (x+4)\cdot (x+2)\cdot \left(\frac{x-4}{x-4} \right)\cdot \left[\frac{x-5}{(x-5)^{2}} \right] Modulative and commutative properties/Associative property

6) \frac{(x+4)\cdot (x+2)}{3\cdot (x-5)}  \frac{a^{m}}{a^{n}} = a^{m-n}/\frac{a}{b}\times \frac{c}{d} = \frac{a\cdot c}{b\cdot d}/Definition of division/Result

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3 years ago
Please help me out I’ll give brainliest
yaroslaw [1]

Answer:6

Step-by-step explanation:

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