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zzz [600]
2 years ago
7

A triangular playground has sides that are lengths 2x feet, x-1 feet and x feet. If the perimeter of this playground is 27 feet,

what are the
lengths of each side of the playground?
Mathematics
1 answer:
Keith_Richards [23]2 years ago
7 0

Answer:

The lengths of the sides of the playground are 14 feet, 6 feet, 7 feet

Step-by-step explanation:

At first, let us find the perimeter of the playground

∵ Perimeter of a triangle is P = S1 + S2 + S3

∵ The sides of the triangular playground are (2x) ft, (x - 1) ft, and x ft

∴ S1 = 2x, S2 = x - 1, S3 = x

→ Substitute them in the rule of the perimeter above

∵ P = 2x + x - 1 + x

→ Add the like terms

∴ P = (2x + x + x) - 1

∴ P = 4x - 1

∵ The perimeter of this playground is 27 feet

∴ P = 27

→ Equate the two values of P

∴ 4x - 1 = 27

→ Add 1 to both sides

∴ 4x - 1 + 1 = 27 + 1

∴ 4x = 28

→ Divide both sides by 4

∵ \frac{4x}{4} = \frac{28}{4}

∴ x = 7

→ Substitute the value of x in each side to find their lengths

∵ S1 = 2(7)

∴ S1 = 14 feet

∵ S2 = 7 - 1

∴ S2 = 6 feet

∵ S3 = 7 feet

∴ The lengths of the sides of the playground are 14 feet, 6 feet, 7 feet

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Answer:

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Step-by-step explanation:

You are solving for the price of one watermelon (a unit of watermelon).

What is given to you is the price of 4 watermelons, or $3.60. To solve, simply divide $3.60 with 4:

3.60/4 = 0.90

$0.90 is your answer.

Remember to add the hundredth place value (0), as money goes to the hundredth place value.

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The length of the
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3 years ago
14. BUS TRIP A bus leaves at 10 A.M. to take students on a field trip to a
k0ka [10]

The bus is 54.5 miles far from the site at the time of 11:30A.M as per the given information in the question.

<h3>What is the slope of a line?</h3>

The slope of a line indicates how steep it is. Slope is defined mathematically as "climb over run" (change in y divided by change in x).

It is assumed that a bus moving at a constant speed departs at 10 a.m. towards a historic location, is 100 miles away by 10:25 a.m., and is 65 miles away at 11:15 a.m.

We must create a point-slope equation that connects the distance from the place to the time in minutes after 10:00 a.m. Then, around 11:30 a.m., we need to figure out how far the bus is from the site.

A line's point-slope is y₂-y₁)=m(x₂-x₁)

Since x denotes the amount of minutes after 10:00 a.m., 10:25 a.m. is represented by x=25 and 11:15 a.m. by x=75.

At 10:25 a.m., a distance of 100 miles from the place is represented by 75.

The point represents a distance of 100 miles from the site at 10:25 a.m. The point represents a distance of 65 miles from the site at 11:15 a.m.

By substituting the points (25, 100) and (75, 65) into the slope formula and simplifying we get,

m=(y₂-y₁)/(x₂-x₁)

m=(65-100)/(75-25)

m=-35/50

m=-0.7

Now choose one of the points and substitute that point and the slope into the slope-point form

y₋y₁=m(x-x₁)

By choosing (x₁, y₁)=(25, 100)

By choosing (x₂, y₂)=(75, 65)

Since 11:30 A,M is 90 minutes after 10:00A.M

By substituting x=90 in the equation we get the value of y,

y-100= -0.7(90-25)

y-100= -0.7(65)

y-100 =-45.5

y= 54.5

Hence, the bus is 54.5 miles from the site at the time of 11:30 A.M

y-100= -0.7(x-25)

OR

y-65= -0.7(x-75)

The bus is 54.5 miles from the site at 11:30A.M.

To know more about slope of a line, visit:

brainly.com/question/28771374

#SPJ9

6 0
1 year ago
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