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3 years ago

Saleh is delivering newspapers for his part-time job. He needs to deliver 30 newspapers and has distributed 10 so far.

1 answer:

3 0

He has delivered 33.3% of his papers. Think of it as a fraction 10/30. Now 100% is 30 papers. 1/3 of that, which is our fraction reduced, is where you get 33.3%. If you divide 100 into thirds (100/3), you get the percent.

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What is 0.65 repeating times 11 over 5

topjm [15]

Firstly, write out as a number, using a few repeats of the decimal. If we multiply this number by 10 it will give a different number with the same digit recurring. When two digits recur multiply by 100 so that the recurring digits after the decimal point keep the same place value.

4 0

4 years ago

Let X equal the number of hours that a randomly selected person from City A reads the news online each day. Suppose that X has a

Nina [5.8K]

Answer:

$P(Y>X) = \frac{17}{32}$

Step-by-step explanation:

Recall that since X is uniformly distributed over the set [1,4] we have that the pdf of X is given by $f(x) = \frac{1}{3}$ if $1\leq x \leq 4$ and 0 otherwise. In the same manner, the pdf of Y is given by $g(y) = \frac{1}{4}$ if $1\leq y\leq 5$ and 0 otherwise.

Note that if Y is in the interval (4,5] then Y>X by default. So, in this case we have that P(Y>X| y in (4,5]) = 1. We want to calculate the probability of having Y in that interval . That is

$P(Y>4) = \int_{4}^{5}\frac{1}{4}dy = \frac{1}{4}$ . Thus, $P(Y\leq 4 ) = 1 - P(Y>4)= \frac{3}{4}$ .

We want to proceed as follows. Using the total probability theorem, given two events A, B we have that

$P(A) = P(A|B)\cdot P(B) + P(A|B^c) \cdot P(B^c)$ In this case, A is the event that Y>X and B is the event that Y is in the interval (4,5].

If we assume that X and Y are independent, then we have that the joint pdf of X,Y is given by $h(x,y) = f(x)g(y) = \frac{1}{12}$ when $1\leq x \leq 4, 1\leq y \leq 4$ . We can draw the region were Y>X and the function h(x,y) is different from 0. (The drawing is attached). This region is described as follows: $1\leq x \leq 4$ and $x\leq y \leq 4$ , then (the specifics of the calculations of the integrals are ommitted)

$P(Y>X| y \in [1,4)) = \int_{1}^{4}\int_{x}^{4}\frac{1}{12}dy dx = \frac{1}{12}\int_{1}^{4} (4-x) dx = \frac{1}{12}\left.(4x-\frac{x}{2})\right|_{1}^{4}= \frac{1}{12}(4\cdot 4 - \frac{4^2}{2}-(4-\frac{1}{2}) = \frac{9}{2\cdot 12} = \frac{3}{8}$

Thus,

$P(Y>X) = 1\cdot \frac{1}{4} + \frac{3}{8}\cdot \frac{3}{4} = \frac{17}{32}$

5 0

4 years ago

The binomial (a+5) is a factor of a2+7a+10. What is the other factor?

aliya0001 [1]

Answer:

(a+2)

Step-by-step explanation:

a²+7a+10 = (a + 5) (a + 2)

a + 5

X <em>5a + ?a = 7a => 5a + 2a = 7a, 5 × ? = 10 => 5 × 2 = 10</em>

a + <em>2</em>

______

(a + 5) (a + 2)

5 0

3 years ago

PLEASE HELP!!!!

Semmy [17]

You should put 4 as x, -3 as y and a as slope to make an equation :
$- 3 = a \times 4$
then you can find the slope and the correct equation of the line :

the slope is :
$- 3 = 4a \\ a = \frac{ - 3}{4}$
so the equation of the line will be
$y = \frac{ - 3}{4} x$
D is true
hope this helps

5 0

3 years ago

How do I solve 9+17a+abc?

kow [346]

This is not an equation, so you can't solve it.
You can't simplify it either because there are no like terms.

4 0

3 years ago