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drek231 [11]
3 years ago
11

What is the place value of the 3 in the number 40,328,960 ​

Mathematics
1 answer:
ANTONII [103]3 years ago
3 0
300,000 or three hundred- thousand. :)
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use the given endpoint r and midpoint m to line rs to find the coordinates of the other endpoint s. r(6,0) m(0,2)
Ganezh [65]
I believe it will be (0,-4)
5 0
3 years ago
Solve equation 3 - 8c = 35
NeTakaya

We would subtact 3 from both sides allowing the equation to simplify to -8c=32

We would then divide both sides by -8 to equal -4

The final answer C=-4

5 0
3 years ago
Have a look of the drawing... What is "d" value? I have tried many methods but don't find how to solve... Pleaseeee
Phoenix [80]
I´d say "d" is the distance from the eye to the wall. 
Now substracting 1.2-1 you´ll get the distance of the wall of the smallest triangle = 0.2 And you do 1.5-0.2= 0.3 that´s the distance of the wall of the other triangle. Then you solve everything with Pitagoras theorem. You have 2 rectangle triangles.
B+alfa=45°
tan^-1(0.2/d)=B
tan^-1(1.3/d)=alfa
THEN:
tan^-1(0.2/d)+tan^-1(1.3/d)=45°
 Now you have 3 ecs and 3 variables.
alfa,B and "d"

3 0
3 years ago
Read 2 more answers
What is the retail price of a shirt that has a wholesale price of $12 and is marked up by 60 percent?
Soloha48 [4]

Answer: 19.20

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Let me know if this was helpful! :D

7 0
3 years ago
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A particle moves on the hyperbola xy=18 for time t≥0 seconds. At a certain instant, y=6 and dydt=8. What is x that this instant?
professor190 [17]

Answer:

The value of x at this instant is 3.

Step-by-step explanation:

Let x\cdot y = 18, we get an additional equation by implicit differentiation:

x\cdot \frac{dy}{dt}+y\cdot \frac{dx}{dt} = 0 (1)

From the first equation we find that:

x = \frac{18}{y} (2)

By applying (2) in (1), we get the resulting expression:

\frac{18}{y}\cdot \frac{dy}{dt}+y\cdot \frac{dx}{dt} = 0 (3)

y\cdot \frac{dx}{dt}=-\frac{18}{y}\cdot \frac{dy}{dt}

\frac{dx}{dt} = -\frac{18}{y^{2}} \cdot \frac{dy}{dt}

If we know that y = 6 and \frac{dy}{dt} = 8, then the first derivative of x in time is:

\frac{dx}{dt} = -\frac{18}{6^{2}} \cdot (8)

\frac{dx}{dt} = -4

From (1) we determine the value of x at this instant:

x\cdot \frac{dy}{dt} = -y\cdot \frac{dx}{dt}

x = -y\cdot \left(\frac{\frac{dx}{dt} }{\frac{dy}{dt} } \right)

x = -6\cdot \left(\frac{-4}{8} \right)

x = 3

The value of x at this instant is 3.

4 0
3 years ago
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