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Maslowich
3 years ago
12

Trig help ..........

Mathematics
1 answer:
erastovalidia [21]3 years ago
3 0
Letter D

1-sin^2(x) = cos^2(x)

= sin^2(x)/cos^2(x)
= tan^2(x)

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I need help fast
hram777 [196]

Answer:

On a coordinate plane, a line goes through (0, 3) and (2, 4) and another line goes through (0, 3) and (0.75, 0).

This answer almost coincide with option C. I suppose there was a mistype.

Step-by-step explanation:

The system of equations is formed by:

–x + 2y = 6

4x + y = 3

In the picture attached, the solution set is shown.

The first equation goes through (0, 3) and (2, 4), as can be checked by:

–(0) + 2(3) = 6

–(2) + 2(4) = 6

The second goes through (0, 3) and (0.75, 0), as can be checked by:

4(0) + (3) = 3

4(0.75) + (0) = 3

7 0
2 years ago
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10. A box contains five and two-thirds cups of rice. If three fourths of the rice will
sweet [91]

Answer:

5 2/3 - 3/4

5 8/12 - 9/12

4 20/12 - 9/12

4 11/12

4 0
3 years ago
I need this answered as soon as possible
Rzqust [24]

Answer:

34

Step-by-step explanation:

basically you need to actually put something in the black photo there

8 0
3 years ago
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True or false: the equation tan^2x+1=sec^2x
zhenek [66]

ANSWER

True

EXPLANATION

The given trigonometric equation is:

{ \tan}^{2} x + 1 = { \sec}^{2} x

We take the LHS and simplify to arrive at the RHS.

{ \tan}^{2} x + 1 =  \frac{{ \sin}^{2} x}{{ \cos}^{2} x}  + 1

Collect LCM on the right hand side to get;

{ \tan}^{2} x + 1 =  \frac{{ \sin}^{2} x + {\cos}^{2} x}{{ \cos}^{2} x}

This implies that

{ \tan}^{2} x + 1 =  \frac{1}{{ \cos}^{2} x} .

{ \tan}^{2} x + 1 =  {( \frac{1}{ \cos(x) }) }^{2}

{ \tan}^{2} x + 1 =  { \sec}^{2} x

This identity has been verified .Therefore the correct answer is true.

3 0
2 years ago
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harkovskaia [24]

Answer:

Answer choice B

Step-by-step explanation:

When you factor the equation, 12 only has 6x2 to equal the -12x. This means that you'll factor it into (3x-6)(x-2). When you set either of these equal to 0, the x value is 2.

8 0
3 years ago
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