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dybincka [34]
3 years ago
10

Please help me out and answer these i don’t understand!!!!

Mathematics
1 answer:
tamaranim1 [39]3 years ago
3 0

Answer:

VHJSZUUgadJYAVFSY

Step-by-step explanation:

DSBHUDUADGJDG

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What’s the slope of 7x +3y=12
Y_Kistochka [10]

Answer:it is 34

And that's it

5 0
3 years ago
What is the product of two numbers is 48?; What is the formula for finding product of two numbers?; What two numbers have a prod
Nadusha1986 [10]

The two numbers that have a product of 48 are 6 and 8 or 12 and 4, etc. They can be multiplied together to get 48, which is the product of the two numbers.

The formula for finding the product of two numbers is to multiply them together. For example, if you have two numbers, a and b, the product of these two numbers is a multiplied by b or an a x b.

The two numbers that have a product of 48 and a sum of 16 are 4 and 12. You can multiply 4 and 12 together to get 48, and you can add them together to get 16.

When the product of two numbers is one of each number, the other number is 1. This means that when the product of two numbers is the same as one of the numbers, the other number must be 1, as 1 multiplied by any number is always equal to itself.

Learn more about the product of two numbers with an example:

brainly.com/question/27860917

#SPJ4

5 0
1 year ago
What is the initial value of the equation y-3=-7x ?
Ludmilka [50]

The value is 21 Because three represents those to variables which both equal to 21.

6 0
3 years ago
Read 2 more answers
1. Find the sum.<br> 109.526 + 36.42<br> Also show the work please
Kobotan [32]
109.526 + 36.42 equals 145.946
5 0
3 years ago
Read 2 more answers
Please someone help me to prove this..​
Pachacha [2.7K]

Answer:  see proof below

<u>Step-by-step explanation:</u>

Use the following Sum to Product Identities:

\sin x+\sin y=2\sin \bigg(\dfrac{x+y}{2}\bigg)\cos \bigg(\dfrac{x-y}{2}\bigg)\\\\\\\sin x-\sin y=2\cos \bigg(\dfrac{x+y}{2}\bigg)\sin \bigg(\dfrac{x-y}{2}\bigg)\\\\\\\cos x+\cos y=2\cos \bigg(\dfrac{x+y}{2}\bigg)\cos \bigg(\dfrac{x-y}{2}\bigg)\\\\\\\cos x+\cos y=-2\sin \bigg(\dfrac{x+y}{2}\bigg)\sin \bigg(\dfrac{x-y}{2}\bigg)

<u>Proof LHS → RHS</u>

\text{LHS:}\qquad \qquad \qquad \dfrac{\sin 5-\sin 15+\sin 25 - \sin 35}{\cos 5-\cos 15- \cos 25 + \cos 35}

\text{Reqroup:}\qquad \qquad \qquad \dfrac{(\sin 25+\sin 5)-(\sin 35 + \sin 15)}{(\cos 35+\cos 5)-(\cos 25 + \cos 15)}

\text{Sum to Product:}\quad \dfrac{2\sin \bigg(\dfrac{25+5}{2}\bigg)\cos \bigg(\dfrac{25-5}{2}\bigg)-2\sin \bigg(\dfrac{35+15}{2}\bigg)\cos \bigg(\dfrac{35-15}{2}\bigg)}{2\cos \bigg(\dfrac{25+15}{2}\bigg)\cos \bigg(\dfrac{25-15}{2}\bigg)-2\cos \bigg(\dfrac{35+5}{2}\bigg)\cos \bigg(\dfrac{35-5}{2}\bigg)}\text{Simplify:}\qquad \qquad \dfrac{2\sin 15\cos 10-2\sin 25\cos 10}{2\cos 20\cos 15-2\cos 20\cos 5}

\text{Factor:}\qquad \qquad \dfrac{2\cos 10(\sin 15-\sin 25)}{2\cos 20(\cos 15-\cos 5)}

\text{Sum to Product:}\qquad \dfrac{\cos 10\bigg[2\cos \bigg(\dfrac{15+25}{2}\bigg)\sin \bigg(\dfrac{15-25}{2}\bigg)\bigg]}{\cos 20\bigg[-2\sin \bigg(\dfrac{15+5}{2}\bigg)\sin \bigg(\dfrac{15-5}{2}\bigg)\bigg]}

\text{Simplify:}\qquad \qquad \dfrac{\cos 10[2\cos 20\sin (-5)]}{\cos 20[-2\sin 10\sin 5]}\\\\\\.\qquad \qquad \qquad =\dfrac{-2\cos10 \cos 20 \sin 5}{-2\sin 10 \cos 20 \sin 5}\\\\\\.\qquad \qquad \qquad =\dfrac{\cos 10}{\sin 10}\\\\\\.\qquad \qquad \qquad =\cot 10

LHS = RHS:  cot 10 = cot 10   \checkmark

8 0
3 years ago
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