Jamie and Erika were in a race. Jamie could run 15 meters per second. Erika could only run 10 meters per second. So Jamie decide
2 answers:
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Answer:
0.9586
Step-by-step explanation:
From the information given:
7 children out of every 1000 children suffer from DIPG
A screening test designed contains 98% sensitivity & 84% specificity.
Now, from above:
The probability that the children have DIPG is:
= (0.98 × 0.007) + 0.16( 1 - 0.007)
= 0.16574
So, the probability of not having DIPG now is:
= 0.9586
Answer:
The distance between the ice cream shop and Joe's house is the same as the distance between the ice cream shop and the park. So Joe is not closer to the park or his house, he is in the middle.
Step-by-step explanation:
We consider that the ice cream shop is the zero value in the number line. We assume that going north is positive (right side of the number line) and going south is negative (left side of the number line).
The house position is 10 block north of the ice cream shop, so it is represented by the integer 10.
The park is 10 blocks south of the ice cream shop, so it is represented by the integer -10.
The lower absolute value of the integer, the closer position from the ice cream shop.
If we calculate the absollute value of the House position:
|10|=10
Then, we calculate the the absollute value of the Parkposition
|-10|=10
In conclusion, the distance between the ice cream shop and Joe's house is the same as the distance between the ice cream shop and the park. Joe is in the middle.
Given:
p = 7.6% = 0.076, the percentage of people who stay overnight at the hospital.
E = 1.5% = 0.015, margin of error
95% confidence interval.
The standard error is
Es =
where
n = the sample size.
The margin of error is
where
z* = 1.96 at the 95% confidence level.
Because the margin of error is given, there is no need to calculate it.
The 95% confidence interval is
p +/- E = 0.076 +/- 0.015 = (0.061, 0.091) = (6.1%, 9.1%)
Answer:
The 95% confidence interval is between 6.1% and 9.1%.
p = 7.6% = 0.076, the percentage of people who stay overnight at the hospital.
E = 1.5% = 0.015, margin of error
95% confidence interval.
The standard error is
Es =
where
n = the sample size.
The margin of error is
where
z* = 1.96 at the 95% confidence level.
Because the margin of error is given, there is no need to calculate it.
The 95% confidence interval is
p +/- E = 0.076 +/- 0.015 = (0.061, 0.091) = (6.1%, 9.1%)
Answer:
The 95% confidence interval is between 6.1% and 9.1%.