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timama [110]
3 years ago
12

K(x)= -3x - 3; find k(-2)

Mathematics
1 answer:
Anastaziya [24]3 years ago
6 0

Answer:

\huge{k( - 2)} = 3

Step-by-step explanation:

K(x)= -3x - 3

To find the value of k substitute the value of k that's -2 into the original expression and solve for the value of k.

That's

k( - 2) =  - 3( - 2) - 3 \\  = 6 - 3 = 3

We have the final answer as

<h3>k(-2) = 3</h3>

Hope this helps you

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Expand the following 2(x+3)
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Step-by-step explanation:

2 will multiply everything inside the bracket.

2 x X =2x

2 X 3=6

6 0
3 years ago
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I will rate you the brainliest (:
Anuta_ua [19.1K]
Az=5
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3 years ago
3 = logb(512)<br><img src="https://tex.z-dn.net/?f=%20log_%7Bb%7D%28512%29%20" id="TexFormula1" title=" log_{b}(512) " alt=" log
zzz [600]

Answer:

<h2>b = 8</h2>

Step-by-step explanation:

\text{Use}\ \log_ab=c\iff a^c=b,\ \text{for}\ a>0,\ b>0\ \wedge\ a\neq1\\\\Domain:b>0\ \wedge\ b\neq1\\\\\log_b(512)=3\iff b^3=512\to b=\sqrt[3]{512}\\\\\begin{array}{c|c}512&2\\256&2\\128&2\\64&2\\32&2\\16&2\\8&2\\4&2\\2&2\\1\end{array}\\\\512=2^9=2^{3\cdot3}=(2^3)^3=8^3\\\\\text{Therefore}\ b=\sqrt[3]{512}=\sqrt[3]{8^3}=8\in D

\text{Used:}\\\\(a^n)^m=a^{nm}\\\\\sqrt[n]{a^n}=a

6 0
3 years ago
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5 0
3 years ago
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