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3 years ago

Andre can run 2 1/2 miles in 3/4 hour. Find his average speed in miles per hour.

Mathematics

2 answers:

PolarNik [594]3 years ago

8 0

Answer:

3 1/3 mph

Step-by-step explanation:

-____________________-

cestrela7 [59]3 years ago

7 0

Answer:

3 1/3 miles per hour

Step-by-step explanation:

(5/2 ÷ 3/4) = (s ÷1)

(5/2 ÷ 3/4) = 10/3

10/3 = s/1

cross-multiply:

3s = 10

s = 10/3

s = 3 1/3 miles per hour

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Andre hit a golf ball from the ground and its movement follows the equation hbracket(t)=-16sup(t,2)+44t, where t is the time in

Natasha2012 [34]

Answer: the golf ball with hit the ground again after 2.75 seconds

Step-by-step explanation:

The movement of the golf ball from the ground follows the equation h(t)=-16t^2+44t,

where t is the time in seconds, and h(t) is the height of the ball at a given time t

By the time the golf ball hit the ground, the height from the ground would be zero. This means that we would equate the quadratic equation to zero. It becomes

-16t^2+44t = 0

Dividing both sides by t

16t^2/t = 44t/t

16t = 44

t = 44/16

t = 2.75

4 0

2 years ago

Will mark bianleast

Galina-37 [17]

Left 7 units and up 3 units

8 0

3 years ago

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One month Amy rented 4 movies and 8 video games for a total of 61 dollars. The next month she rented 2 movies and 3 video games

natulia [17]

Answer:

Rental cost of movie is $6.50 ; Rental cost of video game is $2.25

Step-by-step explanation:

4m + 8v = 61 ........ (1)

2m + 3v = 24 ........ (2)

(1) - 2 × (2)

2v = 13

v = 6.5

2m + 3(6.5) = 24

2m = 24 - 19.5

m = 4.5 ÷ 2 = 2.25

Rental cost for each movie is $6.50

Rental cost for each video game is $2.25

5 0

2 years ago

When a cold drink is taken from a refrigerator, its temperature is 5 degrees C. After 25 minutes in a 20 degrees C room its temp

Leto [7]

Using Newton's Law of Cooling, $\dfrac{dT}{dt} = k(T-T_s)$ , we have $\dfrac{dT}{dt} = k(T - 20)$ ( $T_s$ is 20 degrees). Letting $y = T - 20$ , we get $\dfrac{dy}{dt} = ky$ , so $y(t) = y(0)e^{kt}$ . $y(0) = T(0) - 20 = 5-20 = -15$ , so $y(25) = y(0) e^{25k} = -15e^{25k}$ , and $y(25) = T(25) - 20 = 10 - 20 = -10$ so $-15e^{25k} = -10 \ \ \Rightarrow \ \ e^{25k} = \frac{2}{3}$ . Thus, $25k = \ln\left(\frac{2}{3}\right)$ and $k = \frac{1}{25} \ln\left(\frac{2}{3}\right)$ , so $y(t) = y(0)e^{kt} = -15e^{(1/25)\ln(2/3)t}$ . More simply,
$e^{25k} = \frac{2}{3} \ \ \Rightarrow \ \ e^k = \left( \frac{2}{3} \right)^{1/25}\\ \Rightarrow \ \ e^{kt} = \left( \frac{2}{3} \right)^{t/25}\\
\Rightarrow y(t) = -15 \cdot \left( \frac{2}{3}\right)^{t/25}$

(a) $T(50) = 20 + y(50) = 20-15 \cdot \left( \frac{2}{3}\right)^{50/25}$ =
$20 - 15 \cdot\left(\frac{2}{3}\right)^2 = 20 - \frac{20}{3} = 13.\overline{3}{}^{\circ}C$

13.33333 °C

(b) $15 = T(t) = 20 + y(t) = 20 - 15\cdot\left( \frac{2}{3} \right)^{t/15}$
$\Rightarrow 15 \cdot \left(\frac{2}{3}\right)^{t/25} = 5 \Rightarrow \left( \frac{2}{3} \right)^{t/25} = \frac{1}{3} \Rightarrow$
$(t/25) \ln\left( \frac{2}{3}\right) = \ln\left( \frac{1}{3}\right) \rightarrow t = 25 \ln\left( \frac{1}{3}\right) / \ln\left( \frac{2}{3}\right) \approx 67.74\text{ min}$

67.74 min

4 0

3 years ago

Is 5.97 a rational number? This assignment is graded so i need help

makkiz [27]

Answer:

this is not a rational number

Step-by-step explanation:

cause you cant put it as a fraction

8 0

3 years ago

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