21 picks
altogether (2x+5x)=21
7x=21
x=3
2*3=6 orange picks
or
x=orange, y = greens
x+y=21
x/y=2/5,----> y=5x/2
x+5x/2=21
2x/2+5x/2=21
7x/2=21
7x=42,
x=6 orange picks
Answer: p-8
Step-by-step explanation:first thins problem is impossible without knowing the lifespan of a puma. But if you knew it oh let’s say it was 20 you would subtract the puma by 8.
I’m sure your answer is D. 180 - 125 will get you 55.!
Have a nice day!
Answer:
Step-by-step explanation:
y+ 20= x+ 15( Vertically opposite angles)
y+ 20- 15= x
x= y+ 5 __(1)
3x+ 5=4y- 15
Substituting (1)
3(y+5)+ 5= 4y-15
3y+15+5=4y- 15
y=15+20
y= 35
x= 40
So I'm hoping you mean 6, or else the probability is 0. So the possible ways of getting a sum of 6 is 1&5, 2&4, 3&3, 4&2, 5&1. There are 36 different ways of rolling the dice, so divide the 5 possible ways by 36. Then, we need to add the possibility of getting at least one 6 in the roll. It doesn't matter what the other die is, so for each die, the probability is 1/6, and for both, the probability is 2/6. Add this to the probability of getting a sum of 6, and you get your answer.
